If the volume of a right circular cone of height 9cm is 48π cm3, find the diameter of its base.
Answer
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Hint: The formula of the volume of cone can be used and the given values can be substituted to find the unknown.
Volume of cone $ = 1/3\pi {r^2}h $
Substitute given values, so as to find the unknown.
Complete step-by-step answer:
Given : Volume of Cone $ = 48\pi $ cm3
Height of cone = 9 cm
Let the radius of the cone be r.
We Know,
Volume of Cone $ = 1/3\pi {r^2}h $
Therefore,
$ 1/3\pi {r^2}h $ $ = 48\pi $
Calculating for r:
$ {r^2} = (48\pi \times 3)/(\pi h) $
Substituting the value of h:
$ {r^2} = (48\pi \times 3)/(9\pi ) $
$ {r^2} = 16 $
Square rooting both sides:
$ \sqrt {{r^2}} = \sqrt {16} $
$ r = 4 $ cm
Diameter= 2 x radius
$ D = 2r $
$ D = 2 \times 4 $
$ D = 8 $ cm
Therefore, the diameter of the base of the right circular cone is 8 cm
Note: The Right circular cone has a circular base and its axis is perpendicular to the plane of the base.
The curved surface area of a right circular cone equals the perimeter of the base times one-half slant height. The total surface area equals the curved surface area of the base.
Volume of cone $ = 1/3\pi {r^2}h $
Substitute given values, so as to find the unknown.
Complete step-by-step answer:
Given : Volume of Cone $ = 48\pi $ cm3
Height of cone = 9 cm
Let the radius of the cone be r.
We Know,
Volume of Cone $ = 1/3\pi {r^2}h $
Therefore,
$ 1/3\pi {r^2}h $ $ = 48\pi $
Calculating for r:
$ {r^2} = (48\pi \times 3)/(\pi h) $
Substituting the value of h:
$ {r^2} = (48\pi \times 3)/(9\pi ) $
$ {r^2} = 16 $
Square rooting both sides:
$ \sqrt {{r^2}} = \sqrt {16} $
$ r = 4 $ cm
Diameter= 2 x radius
$ D = 2r $
$ D = 2 \times 4 $
$ D = 8 $ cm
Therefore, the diameter of the base of the right circular cone is 8 cm
Note: The Right circular cone has a circular base and its axis is perpendicular to the plane of the base.
The curved surface area of a right circular cone equals the perimeter of the base times one-half slant height. The total surface area equals the curved surface area of the base.
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