Question

If the sunshine is totally polarized by reflection, then the angle between reflected and refracted light is ?

Answer 1

Hint: Light, electromagnetic wave which will be detected by the human eye.Electromagnetic waves occur over a particularly wide selection of wavelengths, from gamma rays with wavelengths but about $1 \times {10^{11}}$ metre to radio waves measured in meters.

Complete step by step answer:
Whenever the reflected light is completely polarized, therefore the angle between reflected and refracted rays becomes $90^{\circ}$. There's one particular angle of incidence, called polarizing angle ($θ_p$) or Brewster’s angle at which polarization of the reflected ray is complete.

This happens when reflected rays and refracted rays are at right angles to each other. The polarization angle ( also called Brewster's angle)is defined because the angle of incidence at which light with a specific polarization is perfectly transmitted through a transparent dielectric surface, with no reflection.

Brewster's Law states that any tangent of the angle of polarization which is numerically adequate to the index of refraction of the medium.
$μ = \tan i$ .... (1)
From Snell's law: μ = sin r sin i .... 2)
Comparing (1) equation and (2) equation then,
$\cos i = \sin r = \cos (2π - r)\,\text{i.e.}\, i = (2π - r)\,\text{So,}\, i + r = 2π $
Then, if $i + r = 90^{\circ}$

Hence,the angle between reflected ray and refracted ray are going to be $180^{\circ} - 90^{\circ} = 90^{\circ}$.

Note: For a selected angle of incidence (p), called the polarizing angle or Brewster's angle, all reflected waves will vibrate perpendicular to the plane of incidence (i.e., to the surface), and therefore therefore the reflected ray and the refracted ray are going to be separated by 90°.