What if the inverse cosine of $ 0.55 $ ?
Answer
524.4k+ views
Hint: In order to find the inverse cosine of $ 0.55 $ , we need to know about the inverse function. Inverse function is also known as anti-function. Basically, the inverse of a function is the reverse of a function. The inverse is not a function. The inverse of a function is denoted by a function with power of $ - 1 $ , as $ {f^{ - 1}}\left( x \right) $ .
Complete step-by-step answer:
We are given $ 0.55 $ , to find the cosine inverse.
Since, we know that the inverse of a function is the reverse of a function and it’s denoted by $ {f^{ - 1}}\left( x \right) $ .
So, for the cosine inverse it can be represented or written as $ {\cos ^{ - 1}}\left( x \right) $ .Substituting the value of $ x $ as $ 0.55 $ .
Now, the cosine inverse of $ 0.55 $ is written as $ {\cos ^{ - 1}}\left( {0.55} \right) $ .
Consider a function to be $ \cos \theta = 0.55 $ , where $ \theta $ is an angle.
Multiplying $ {\cos ^{ - 1}} $ both sides, we get:
$ {\cos ^{ - 1}}\left( {\cos \theta } \right) = {\cos ^{ - 1}}\left( {0.55} \right) $
$ \theta = {\cos ^{ - 1}}\left( {0.55} \right) $
So, we can see we need to find the angle whose value is $ 0.55 $ .
But, we only the values of the angles such as $ {30^ \circ } $ , $ {45^ \circ } $ , $ {60^ \circ } $ and $ {90^ \circ } $ , and for no cosine angle, it gives $ 0.55 $ .
So, we need to use scientific calculator and using that we get:
$ {\cos ^{ - 1}}\left( {0.55} \right) = 56.6329870308 $
Since, it is an angle so it’s in degrees.
Also, written as:
$ {\cos ^{ - 1}}\left( {0.55} \right) = {56.6329870308^ \circ } $
$ {\cos ^{ - 1}}\left( {0.55} \right) \approx {57^ \circ } $
Therefore, the inverse cosine of $ 0.55 $ is $ {56.6329870308^ \circ } $ or $ {\cos ^{ - 1}}\left( {0.55} \right) \approx {57^ \circ } $ .
Note: If needed we can change the value of inverse cosine from degrees to radian.
We can also use an approximation method to find the angle for the value by finding the values at other angles, then deciding in which range it could lie.
It’s important to use a scientific calculator when there is no value or angle is known.
Complete step-by-step answer:
We are given $ 0.55 $ , to find the cosine inverse.
Since, we know that the inverse of a function is the reverse of a function and it’s denoted by $ {f^{ - 1}}\left( x \right) $ .
So, for the cosine inverse it can be represented or written as $ {\cos ^{ - 1}}\left( x \right) $ .Substituting the value of $ x $ as $ 0.55 $ .
Now, the cosine inverse of $ 0.55 $ is written as $ {\cos ^{ - 1}}\left( {0.55} \right) $ .
Consider a function to be $ \cos \theta = 0.55 $ , where $ \theta $ is an angle.
Multiplying $ {\cos ^{ - 1}} $ both sides, we get:
$ {\cos ^{ - 1}}\left( {\cos \theta } \right) = {\cos ^{ - 1}}\left( {0.55} \right) $
$ \theta = {\cos ^{ - 1}}\left( {0.55} \right) $
So, we can see we need to find the angle whose value is $ 0.55 $ .
But, we only the values of the angles such as $ {30^ \circ } $ , $ {45^ \circ } $ , $ {60^ \circ } $ and $ {90^ \circ } $ , and for no cosine angle, it gives $ 0.55 $ .
So, we need to use scientific calculator and using that we get:
$ {\cos ^{ - 1}}\left( {0.55} \right) = 56.6329870308 $
Since, it is an angle so it’s in degrees.
Also, written as:
$ {\cos ^{ - 1}}\left( {0.55} \right) = {56.6329870308^ \circ } $
$ {\cos ^{ - 1}}\left( {0.55} \right) \approx {57^ \circ } $
Therefore, the inverse cosine of $ 0.55 $ is $ {56.6329870308^ \circ } $ or $ {\cos ^{ - 1}}\left( {0.55} \right) \approx {57^ \circ } $ .
Note: If needed we can change the value of inverse cosine from degrees to radian.
We can also use an approximation method to find the angle for the value by finding the values at other angles, then deciding in which range it could lie.
It’s important to use a scientific calculator when there is no value or angle is known.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

