If the first term of a finite A.P. is \[5\], the last term is \[45\] and the sum is \[500\]. Find the number of terms. If the first term and last term of a finite A.P. are \[5\] and \[95\] respectively and \[d = 5\], find \[n\] and \[{S_n}\].
Answer
652.8k+ views
Hint: Use sum of the first term and last term of an AP then substitute the value of first term, last term and sum in the formula of sum of the first term and last term of an AP then find the value of \[n\]. Again, use the sum of the first \[n\] terms of an AP and find the value of \[n\] and \[{S_n}\].
Complete step by step answer:
Given, The first term of a finite A.P. \[a\] is 5.
The last term of a finite A.P. \[l\] is 45.
The sum of a finite A.P. \[{S_n}\] is 500.
We have, sum of first n terms of an A.P. is given as, \[{S_n} = \dfrac{n}{2}\left( {a + l} \right)\] …(i)
Where, Sn is sum of first n terms, n is number of terms, a is first term and l is the last term.
Substitute the value of \[a = 5\], \[{S_n} = 500\] and \[l = 5\] in equation (i), we have
\[
500 = \dfrac{n}{2}\left( {5 + 45} \right) \\
\Rightarrow 1000 = 50n \\
\]
Divide by \[50\] on both the sides.
\[\dfrac{{50n}}{{50}} = \dfrac{{1000}}{{50}} \Rightarrow n = \dfrac{{100}}{5} \Rightarrow n = 20\]
Therefore, the number of terms of a finite A.P., n is \[20\].
The first term of a finite A.P. \[a\] is 5.
The last term of a finite A.P. \[l\] is 95.
The common difference of a finite A.P. \[d\] is 5.
The sum of the first \[n\] terms of an AP is given by \[{S_n} = \dfrac{n}{2}\left( {a + l} \right)\].
Substitute the value of \[a = 5\] and \[l = 95\] in \[{S_n} = \dfrac{n}{2}\left( {a + l} \right)\].
\[{S_n} = \dfrac{n}{2}\left( {5 + 95} \right) = \dfrac{n}{2} \cdot 100 = 50n\]
So,
\[\dfrac{n}{2}\left( {a + \left( {n - 1} \right)d} \right) = 50n\] … (ii)
Substitute the value of \[a = 5\] and \[d = 5\] in equation (ii).
\[
\dfrac{n}{2}\left( {5 + \left( {n - 1} \right)5} \right) = 50n \\
\Rightarrow \dfrac{1}{2}\left( {5 + 5n - 5} \right) = 50 \\
\Rightarrow \dfrac{1}{2}\left( {5n} \right) = 50 \\
\Rightarrow 5n = 100 \\
\]
Divide by 5 on both the sides, we get
\[\dfrac{{5n}}{5} = \dfrac{{100}}{5} \Rightarrow n = 20\]
Therefore, the number of terms of a finite A.P. is \[20\].
Substitute the value of \[n = 20\] in \[{S_n} = 50n\].
\[{S_n} = 50n = 50 \times 20 = 1000\]
Therefore, the sum of first \[20\] terms of an AP is \[1000\].
Note:
In these types of questions, use formulas of AP very carefully. First see, what elements are given in question, and then choose the appropriate formula, because one formula can give value of only one variable.
Complete step by step answer:
Given, The first term of a finite A.P. \[a\] is 5.
The last term of a finite A.P. \[l\] is 45.
The sum of a finite A.P. \[{S_n}\] is 500.
We have, sum of first n terms of an A.P. is given as, \[{S_n} = \dfrac{n}{2}\left( {a + l} \right)\] …(i)
Where, Sn is sum of first n terms, n is number of terms, a is first term and l is the last term.
Substitute the value of \[a = 5\], \[{S_n} = 500\] and \[l = 5\] in equation (i), we have
\[
500 = \dfrac{n}{2}\left( {5 + 45} \right) \\
\Rightarrow 1000 = 50n \\
\]
Divide by \[50\] on both the sides.
\[\dfrac{{50n}}{{50}} = \dfrac{{1000}}{{50}} \Rightarrow n = \dfrac{{100}}{5} \Rightarrow n = 20\]
Therefore, the number of terms of a finite A.P., n is \[20\].
The first term of a finite A.P. \[a\] is 5.
The last term of a finite A.P. \[l\] is 95.
The common difference of a finite A.P. \[d\] is 5.
The sum of the first \[n\] terms of an AP is given by \[{S_n} = \dfrac{n}{2}\left( {a + l} \right)\].
Substitute the value of \[a = 5\] and \[l = 95\] in \[{S_n} = \dfrac{n}{2}\left( {a + l} \right)\].
\[{S_n} = \dfrac{n}{2}\left( {5 + 95} \right) = \dfrac{n}{2} \cdot 100 = 50n\]
So,
\[\dfrac{n}{2}\left( {a + \left( {n - 1} \right)d} \right) = 50n\] … (ii)
Substitute the value of \[a = 5\] and \[d = 5\] in equation (ii).
\[
\dfrac{n}{2}\left( {5 + \left( {n - 1} \right)5} \right) = 50n \\
\Rightarrow \dfrac{1}{2}\left( {5 + 5n - 5} \right) = 50 \\
\Rightarrow \dfrac{1}{2}\left( {5n} \right) = 50 \\
\Rightarrow 5n = 100 \\
\]
Divide by 5 on both the sides, we get
\[\dfrac{{5n}}{5} = \dfrac{{100}}{5} \Rightarrow n = 20\]
Therefore, the number of terms of a finite A.P. is \[20\].
Substitute the value of \[n = 20\] in \[{S_n} = 50n\].
\[{S_n} = 50n = 50 \times 20 = 1000\]
Therefore, the sum of first \[20\] terms of an AP is \[1000\].
Note:
In these types of questions, use formulas of AP very carefully. First see, what elements are given in question, and then choose the appropriate formula, because one formula can give value of only one variable.
Recently Updated Pages
Onehalf of a convex lens is covered with a black paper class 12 physics CBSE

Differentiate between lanthanoids and actinoids class 12 chemistry CBSE

An object 5 cm in length is held 25 cm away from a class 12 physics CBSE

Name the following halides according to the IUPAC system class 12 chemistry CBSE

What is the Full Form of PVC, PET, HDPE, LDPE, PP and PS ?

An infinite ladder network of resistances is constructed class 12 physics CBSE

Trending doubts
Draw a labelled sketch of the human eye class 12 physics CBSE

Which are the Top 10 Largest Countries of the World?

Draw ray diagrams each showing i myopic eye and ii class 12 physics CBSE

Which is the correct genotypic ratio of mendel dihybrid class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Give 10 examples of unisexual and bisexual flowers

