Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

If the birth rate is 100, death rate is 10 and the number of individuals in the population group is 1000, then what will be the percentage of natural growth?

Answer
VerifiedVerified
467.1k+ views
Hint: Natural growth is the rate of increase or decrease in the population of species for a specific period of time (Generally a year). It can be either positive or negative. The factor affecting Natural growth is natality (birth Rate), mortality (death rate), immigration and emigration. Natality and immigration will increase Natural growth whereas mortality and emigration will decrease Natural Growth.

When the number of live births exceeds the number of deaths within the period under consideration, a population rise occurs. When the number of deaths exceeds the number of births, a population decline occurs.

Complete answer:
In our case, both the Death and the birth rate are given.
$DeathRate = 10$ $BirthRate = 100$
The number of individuals in the group is $Population = 1000$
Percentage of natural Growth is defined as the difference between Birth rate and death rate divided by the population of that year or at the end of the year multiplied by $100$.
$Growth = \dfrac{{BirthRate - DeathRate}}{{Population}} \times 100$
The difference between Birth rate and Death Rate is $90$, So
\[Growth = \dfrac{{90}}{{1000}} \times 100 = 9\% \]

The Percentage of natural Growth of the population of $1000$ with a Birth rate $100$ and a Death Rate is $9\% $.

Note: Growth mainly depends on two factors that are Birth Rate and Death Rate. If the birth rate exceeds the death rate, then there is positive growth. When the death rate exceeds the birth rate then there is negative growth.