Question

# If six times of a number is 48, then the number is\begin{align} & \text{A}.-\text{8} \\ & \text{B}.\text{ 1} \\ & \text{C}.\text{ 48} \\ & \text{D}.\text{ 8} \\ \end{align}

Hint: To solve this question, we will first of all assume a variable x to be the number, then, we would use the given condition to form a linear equation in a single variable. As per first condition, we have 6 times the number i.e. 6x and it is given that it is equal to 48. So, we will equate these two numbers and solving this would give the required result.

Let us assume, a variable x to be the number. Now, 'six times' indicates that the number is being multiplied with 6. We can also say that the number is being added 6 times. So, using this information, we can write six times a number, x as $6x\Rightarrow x+x+x+x+x+x$. Here, we will take it as 6x. Then, according to given condition in the question, we have
$6x=48$
$x=\dfrac{48}{6}$
$x=8$
Note: The key point to note or the possibility of mistake in this question can be assuming -8 as the number that is option A. This is wrong, as we are given six times of the number is 48 and not -48. If it was -48 then we would have $6x=-48\Rightarrow x=-8$ but here, we had $6x=48\Rightarrow x=8$ is the correct answer.