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Question

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\[\begin{align}

& \text{A}.-\text{8} \\

& \text{B}.\text{ 1} \\

& \text{C}.\text{ 48} \\

& \text{D}.\text{ 8} \\

\end{align}\]

Answer
Verified

Given that, six times of a number is 48.

Let us assume, a variable x to be the number. Now, 'six times' indicates that the number is being multiplied with 6. We can also say that the number is being added 6 times. So, using this information, we can write six times a number, x as $6x\Rightarrow x+x+x+x+x+x$. Here, we will take it as 6x. Then, according to given condition in the question, we have

\[6x=48\]

Dividing both sides by 6, we get:

\[x=\dfrac{48}{6}\]

Dividing 48 by 6, we get:

\[x=8\]

So, the value of x = 8.

Therefore, the number is nothing but 8.