If Meena gives an interest of Rs. 45 for one year at ${\text{9\% }}$ rate p.a.
What is the sum she has borrowed?
Last updated date: 25th Mar 2023
•
Total views: 310.5k
•
Views today: 3.87k
Answer
310.5k+ views
Hint:-Simple Interest $ = \dfrac{{{\text{(principle value)*(Interest rate)*(time period)}}}}{{100}}$
As, we are given with simple interest, rate of interest and time period.
And asked for the initial amount borrowed by Meena.
$ \Rightarrow $So, Simple interest $ = {\text{ }}Rs45$
$ \Rightarrow $Rate for interest for 1 year is ${\text{9\% }}$p.a.
$ \Rightarrow $Time period $ = $ 1 Year
And as we know that formula for Simple Interest $(S.I)$ is calculated as,
$ \Rightarrow S.I. = \dfrac{{PRT}}{{100}}$ (1)
Where,
P $ = $ Principle amount or initial amount borrowed (we had to find)
R $ = $ Rate of interest on the initial amount borrowed by Meena.
T $ = $ Time period
S.I $ = $ Simple Interest
So, now putting the values of S.I, P, T and R in the equation 1. We get,
$ \Rightarrow 45 = \dfrac{{P*9*1}}{{100}}$
Solving the above equation for getting the value of P. We get,
$ \Rightarrow P = \dfrac{{4500}}{9}$
So, P $ = $ Rs 500
$ \Rightarrow $Hence, the amount borrowed by Meena is Rs 500.
Note:- Whenever we came up with this type of question where we are given with
Simple Interest, then we had to use Simple interest formula $\left( {S.I. = \dfrac{{PRT}}{{100}}} \right)$, to
get the required answer.
As, we are given with simple interest, rate of interest and time period.
And asked for the initial amount borrowed by Meena.
$ \Rightarrow $So, Simple interest $ = {\text{ }}Rs45$
$ \Rightarrow $Rate for interest for 1 year is ${\text{9\% }}$p.a.
$ \Rightarrow $Time period $ = $ 1 Year
And as we know that formula for Simple Interest $(S.I)$ is calculated as,
$ \Rightarrow S.I. = \dfrac{{PRT}}{{100}}$ (1)
Where,
P $ = $ Principle amount or initial amount borrowed (we had to find)
R $ = $ Rate of interest on the initial amount borrowed by Meena.
T $ = $ Time period
S.I $ = $ Simple Interest
So, now putting the values of S.I, P, T and R in the equation 1. We get,
$ \Rightarrow 45 = \dfrac{{P*9*1}}{{100}}$
Solving the above equation for getting the value of P. We get,
$ \Rightarrow P = \dfrac{{4500}}{9}$
So, P $ = $ Rs 500
$ \Rightarrow $Hence, the amount borrowed by Meena is Rs 500.
Note:- Whenever we came up with this type of question where we are given with
Simple Interest, then we had to use Simple interest formula $\left( {S.I. = \dfrac{{PRT}}{{100}}} \right)$, to
get the required answer.
Recently Updated Pages
Paulings electronegativity values for elements are class 11 chemistry CBSE

For a particle executing simple harmonic motion the class 11 physics CBSE

Does Nichrome have high resistance class 12 physics CBSE

The function f satisfies the functional equation 3fleft class 12 maths JEE_Main

Write a letter to the Principal of your school to plead class 10 english CBSE

Look at the handout below Write a letter to the organizers class 11 english CBSE

Trending doubts
What was the capital of Kanishka A Mathura B Purushapura class 7 social studies CBSE

Difference Between Plant Cell and Animal Cell

Write an application to the principal requesting five class 10 english CBSE

Ray optics is valid when characteristic dimensions class 12 physics CBSE

Give 10 examples for herbs , shrubs , climbers , creepers

Tropic of Cancer passes through how many states? Name them.

Write the 6 fundamental rights of India and explain in detail

Write a letter to the principal requesting him to grant class 10 english CBSE

Name the Largest and the Smallest Cell in the Human Body ?
