If $a.i = 4,$ then $(a.j) \times (2j - 3k)$ is equal to?
$
1)12 \\
2)2 \\
3)0 \\
4) - 12 \\
$
Answer
516k+ views
Hint: Here we will take the cross product of the given expression by using the properties of the dot and the cross product and accordingly simplify the expression and place the given value in it for the resultant required value.
Complete step-by-step answer:
Take the given expression: $(a.j) \times (2j - 3k)$
Take the multiplicative distribution property in the above expression –
$ = (a.(j \times (2j - 3k))$
Again, apply the additive multiplicative property inside the bracket –
$ = (a.(2(j \times j) - 3(j \times k))$
Now, use the identity $j \times j = 0$ and $j \times k = i$ and place in the above equation –
$ = (a.(2(0) - 3(i))$
When zero is multiplied with any number it gives zero as the resultant value.
$ = - 3a(i))$
The above expression can be re-written as –
$ = - 3(a.i)$
Place the given known in the above expression –
$ = - 3(4)$
Simplify the above expression by finding the product of the terms. When you multiply the positive term and the negative term the resultant term will be negative.
$ = - 12$
Therefore, $(a.j) \times (2j - 3k) = ( - 12)$
So, the correct answer is “Option 4”.
Note: Cross-product can be defined as the vector which is the binary operation on two vectors with the three dimensions. Be careful about the sign convention while finding the product of the terms with different and same signs. When you find the product of two negative or two positive terms the resultant value will be in positive while finding the product of the two terms with different signs then the resultant value will be negative.
Complete step-by-step answer:
Take the given expression: $(a.j) \times (2j - 3k)$
Take the multiplicative distribution property in the above expression –
$ = (a.(j \times (2j - 3k))$
Again, apply the additive multiplicative property inside the bracket –
$ = (a.(2(j \times j) - 3(j \times k))$
Now, use the identity $j \times j = 0$ and $j \times k = i$ and place in the above equation –
$ = (a.(2(0) - 3(i))$
When zero is multiplied with any number it gives zero as the resultant value.
$ = - 3a(i))$
The above expression can be re-written as –
$ = - 3(a.i)$
Place the given known in the above expression –
$ = - 3(4)$
Simplify the above expression by finding the product of the terms. When you multiply the positive term and the negative term the resultant term will be negative.
$ = - 12$
Therefore, $(a.j) \times (2j - 3k) = ( - 12)$
So, the correct answer is “Option 4”.
Note: Cross-product can be defined as the vector which is the binary operation on two vectors with the three dimensions. Be careful about the sign convention while finding the product of the terms with different and same signs. When you find the product of two negative or two positive terms the resultant value will be in positive while finding the product of the two terms with different signs then the resultant value will be negative.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Which state in the country is at the forefront in controlling class 12 social science CBSE

Where is the largest hydroelectric power station located class 12 biology CBSE

Which country did Danny Casey play for class 12 english CBSE

Coming together federation is practiced in A India class 12 social science CBSE

