
If $A:B=3:4$ and $B:C=6:7$ , then $A:B:C$ is $9:12:14$ state true or false.
A.True
B.False
Answer
588.3k+ views
Hint: Use equations $\dfrac{A}{B}=\dfrac{3}{4}$ and $\dfrac{B}{C}=\dfrac{6}{7}$ to get the value of B in terms of a and c individually. Now, get an equation by equating values of B and hence, equate the whole equation to k and get the values of A, B and C in terms of k. Now, find A:B:C with the help of the relation A,B,C in terms of k individually.
Complete step-by-step answer:
Here, ratio of A to B and B to C are given as:
$A:B=3:4$ ………………….. (1)
$B:C=6:7$ …………………… (2)
And hence, we need to verify the statement that value of $A:B:C=9:12:14$ . So, let us find the value of $A:B:C$ with the help of two equations.
So, we can write equation (1) as:
$\dfrac{A}{B}=\dfrac{3}{4}$
On cross-multiplying the above equation, we get:
$4A=3B$ ……………………….. (3)
Similarly, we can write equation (2) as:
$\dfrac{B}{C}=\dfrac{6}{7}$
On cross-multiplying the above equation, we get-
$7B=6C$ ……………………. (4)
Now, we can get value of B from equation (3) as:
$4A=3B$ or
$B=\dfrac{4A}{3}$ ……………………………. (5)
Similarly, we get value of B from equation (4) as:
$B=\dfrac{6C}{7}$ ……………………………. (6)
Now, we can equate equation (5) and (60 as both are representing the values of B. So, we get:
$B=\dfrac{4A}{3}=\dfrac{6C}{7}$ or
$\dfrac{4A}{3}=B=\dfrac{6C}{7}$ …………………………… (7)
Now, on equating the above equation to a real number ‘k’, we can rewrite the equation (7) as:
$\dfrac{4A}{3}=B=\dfrac{6C}{7}=k$ …………………………… (8)
Now, we can get value of A from first and last term of the above equation as:
$A=\dfrac{3k}{4}$
Similarly, value of B, can be given as:
$B=k$
And hence, value of C is also given by the same approach as:
$C=\dfrac{7k}{6}$
Therefore, A:B:C can be given as:
$\dfrac{3k}{4}:\dfrac{k}{1}:\dfrac{7k}{6}$
On dividing the whole equation by ‘k’ and multiplying with the L.C.M of 4, 1, 6 i.e. 12, we get the above relation as:
$\begin{align}
& \dfrac{3k}{4}\times \dfrac{12}{k}:\dfrac{k}{1}\times \dfrac{12}{k}:\dfrac{7k}{6}\times \dfrac{12}{k} \\
& 9:12:14 \\
\end{align}$
So, we get the value of A:B:C as:
\[A:B:C=9:12:14\]
So, the given statement is true as \[A:B:C=9:12:14\] is also given in the problem as well.
Hence, (A) is the correct answer.
Note: Another approach to solve the question would be that:
For, $A:B=3:4$
Suppose $A=3x$ and $B=4x$
For, $B:C=6:7$
Suppose $B=6y$ and $c=7y$
Now, equate 4x and 6y to get relation in x and y and hence, write the values of A, B, C either in x or y to get the value of A: B: C.
We cannot calculate exact values of A, B and C from the given equation. So, don’t confuse yourself with it as we cannot calculate values of three variables using only two equations. So, one may go wrong, If he/she goes for calculating values of A, B, C. Hence, we need to take care of it with the problem and for future reference as well.
Complete step-by-step answer:
Here, ratio of A to B and B to C are given as:
$A:B=3:4$ ………………….. (1)
$B:C=6:7$ …………………… (2)
And hence, we need to verify the statement that value of $A:B:C=9:12:14$ . So, let us find the value of $A:B:C$ with the help of two equations.
So, we can write equation (1) as:
$\dfrac{A}{B}=\dfrac{3}{4}$
On cross-multiplying the above equation, we get:
$4A=3B$ ……………………….. (3)
Similarly, we can write equation (2) as:
$\dfrac{B}{C}=\dfrac{6}{7}$
On cross-multiplying the above equation, we get-
$7B=6C$ ……………………. (4)
Now, we can get value of B from equation (3) as:
$4A=3B$ or
$B=\dfrac{4A}{3}$ ……………………………. (5)
Similarly, we get value of B from equation (4) as:
$B=\dfrac{6C}{7}$ ……………………………. (6)
Now, we can equate equation (5) and (60 as both are representing the values of B. So, we get:
$B=\dfrac{4A}{3}=\dfrac{6C}{7}$ or
$\dfrac{4A}{3}=B=\dfrac{6C}{7}$ …………………………… (7)
Now, on equating the above equation to a real number ‘k’, we can rewrite the equation (7) as:
$\dfrac{4A}{3}=B=\dfrac{6C}{7}=k$ …………………………… (8)
Now, we can get value of A from first and last term of the above equation as:
$A=\dfrac{3k}{4}$
Similarly, value of B, can be given as:
$B=k$
And hence, value of C is also given by the same approach as:
$C=\dfrac{7k}{6}$
Therefore, A:B:C can be given as:
$\dfrac{3k}{4}:\dfrac{k}{1}:\dfrac{7k}{6}$
On dividing the whole equation by ‘k’ and multiplying with the L.C.M of 4, 1, 6 i.e. 12, we get the above relation as:
$\begin{align}
& \dfrac{3k}{4}\times \dfrac{12}{k}:\dfrac{k}{1}\times \dfrac{12}{k}:\dfrac{7k}{6}\times \dfrac{12}{k} \\
& 9:12:14 \\
\end{align}$
So, we get the value of A:B:C as:
\[A:B:C=9:12:14\]
So, the given statement is true as \[A:B:C=9:12:14\] is also given in the problem as well.
Hence, (A) is the correct answer.
Note: Another approach to solve the question would be that:
For, $A:B=3:4$
Suppose $A=3x$ and $B=4x$
For, $B:C=6:7$
Suppose $B=6y$ and $c=7y$
Now, equate 4x and 6y to get relation in x and y and hence, write the values of A, B, C either in x or y to get the value of A: B: C.
We cannot calculate exact values of A, B and C from the given equation. So, don’t confuse yourself with it as we cannot calculate values of three variables using only two equations. So, one may go wrong, If he/she goes for calculating values of A, B, C. Hence, we need to take care of it with the problem and for future reference as well.
Recently Updated Pages
Master Class 8 Social Science: Engaging Questions & Answers for Success

Master Class 8 Maths: Engaging Questions & Answers for Success

Master Class 8 Science: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Master Class 8 English: Engaging Questions & Answers for Success

Master Class 6 English: Engaging Questions & Answers for Success

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Which one of the following groups comprises states class 8 social science CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Full form of STD, ISD and PCO

A couple went for a picnic They have 5 sons and each class 8 maths CBSE

Right to vote is a AFundamental Right BFundamental class 8 social science CBSE


