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(a) $13\times 1\text{ or }1\times 13$

(b) $1\times 26\text{ or 26}\times \text{1}$

(c) $2\times 13\text{ or 13}\times \text{2}$

(d) $13\times 13$

Answer
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Now, we know that the dimensions of a matrix are its number of rows multiplied by the number of columns and the number of elements is the result of the multiplication. So, we know that the number of elements, number of rows and number of columns are integers.

Now, we let the dimension of the matrix be $x\times y$ . So, according to the above constraints, we can say that x, y are non-negative integers, and $xy=13$ .

Now, there are only two sets (x,y) satisfying the condition mentioned above: (13,1) and (1,13). So, the dimensions of the matrix can be $13\times 1\text{ or }1\times 13$ .