Answer
Verified
394.5k+ views
Hint: In this question, we will first evaluate the value of \[a\times \left( a\times r \right)\] given that \[a\times r=b\]. Then using the triple cross product formula \[\overrightarrow{a}\times \left(
\overrightarrow{b}\times \overrightarrow{c} \right)=\left( \overrightarrow{a}\cdot
\overrightarrow{c} \right)\overrightarrow{b}-\left( \overrightarrow{a}\cdot \overrightarrow{b} \right)\overrightarrow{c}\] for vectors \[\overrightarrow{a}\], \[\overrightarrow{b}\] and
\[\overrightarrow{c}\], we will then find the value of \[a\times \left( a\times r \right)\]. Then using the fact that \[a\] is a unit vector we have \[{{a}^{2}}=1\]. We will then substitute the value \[{{a}^{2}}=1\] and \[a\cdot r=c\] in the expression for \[a\times \left( a\times r \right)\] to get the value of \[r\].
Complete step-by-step answer:
We are given a unit vector \[a\].
\[\Rightarrow {{a}^{2}}=1\]
Since we have \[a\times r=b\], thus on evaluating the value of \[a\times \left( a\times r \right)\] by
substituting \[a\times r=b\] we get
\[a\times \left( a\times r \right)=a\times b\]
Now we know that for vectors \[\overrightarrow{a}\], \[\overrightarrow{b}\] and
\[\overrightarrow{c}\], then the triple cross product of vectors \[\overrightarrow{a}\],
\[\overrightarrow{b}\] and \[\overrightarrow{c}\]is given by
\[\overrightarrow{a}\times \left( \overrightarrow{b}\times \overrightarrow{c} \right)=\left(
\overrightarrow{a}\cdot \overrightarrow{c} \right)\overrightarrow{b}-\left( \overrightarrow{a}\cdot
\overrightarrow{b} \right)\overrightarrow{c}\]
Using the above formula for the triple cross product in \[a\times \left( a\times r \right)\], we get that
\[a\times \left( a\times r \right)=\left( a\cdot r \right)a-\left( a\cdot a \right)r\]
Now, using \[a\cdot r=c\] in the above equation we have
\[\begin{align}
& a\times \left( a\times r \right)=\left( a\cdot r \right)a-\left( a\cdot a \right)r \\
& =ca-{{a}^{2}}r
\end{align}\]
Since \[a\times \left( a\times r \right)=a\times b\] , thus we have
\[ca-{{a}^{2}}r=a\times b...........(1)\]
Also \[{{a}^{2}}=1\]where \[a\]is a unit vector.
Therefore substituting the value \[{{a}^{2}}=1\] in equation (1) , we get
\[ca-r=a\times b\]
We will now calculate the value of \[r\] by rearranging the terms of the above equation.
By taking vector \[r\] to the right and taking \[a\times b\] to the left side of the equation we get
\[ca-\left( a\times b \right)=r\]
Therefore the value of \[r\] is given by \[ca-\left( a\times b \right)\]
So, the correct answer is “Option (d)”.
Note: In this problem, we have also use the definition of cross product and dot product to get the
desired value of \[r\]. We have \[a\times b=ab\sin \theta \] where \[\theta \] is the angle between \[a\] and \[b\].
Also \[a\cdot b=ab\cos \theta \]. Then using the fact that \[a\cdot b=0\], we say that vectors \[a\] and \[b\] are orthogonal to each other. That is the vectors \[a\] and \[b\] are perpendicular to each other.
\overrightarrow{b}\times \overrightarrow{c} \right)=\left( \overrightarrow{a}\cdot
\overrightarrow{c} \right)\overrightarrow{b}-\left( \overrightarrow{a}\cdot \overrightarrow{b} \right)\overrightarrow{c}\] for vectors \[\overrightarrow{a}\], \[\overrightarrow{b}\] and
\[\overrightarrow{c}\], we will then find the value of \[a\times \left( a\times r \right)\]. Then using the fact that \[a\] is a unit vector we have \[{{a}^{2}}=1\]. We will then substitute the value \[{{a}^{2}}=1\] and \[a\cdot r=c\] in the expression for \[a\times \left( a\times r \right)\] to get the value of \[r\].
Complete step-by-step answer:
We are given a unit vector \[a\].
\[\Rightarrow {{a}^{2}}=1\]
Since we have \[a\times r=b\], thus on evaluating the value of \[a\times \left( a\times r \right)\] by
substituting \[a\times r=b\] we get
\[a\times \left( a\times r \right)=a\times b\]
Now we know that for vectors \[\overrightarrow{a}\], \[\overrightarrow{b}\] and
\[\overrightarrow{c}\], then the triple cross product of vectors \[\overrightarrow{a}\],
\[\overrightarrow{b}\] and \[\overrightarrow{c}\]is given by
\[\overrightarrow{a}\times \left( \overrightarrow{b}\times \overrightarrow{c} \right)=\left(
\overrightarrow{a}\cdot \overrightarrow{c} \right)\overrightarrow{b}-\left( \overrightarrow{a}\cdot
\overrightarrow{b} \right)\overrightarrow{c}\]
Using the above formula for the triple cross product in \[a\times \left( a\times r \right)\], we get that
\[a\times \left( a\times r \right)=\left( a\cdot r \right)a-\left( a\cdot a \right)r\]
Now, using \[a\cdot r=c\] in the above equation we have
\[\begin{align}
& a\times \left( a\times r \right)=\left( a\cdot r \right)a-\left( a\cdot a \right)r \\
& =ca-{{a}^{2}}r
\end{align}\]
Since \[a\times \left( a\times r \right)=a\times b\] , thus we have
\[ca-{{a}^{2}}r=a\times b...........(1)\]
Also \[{{a}^{2}}=1\]where \[a\]is a unit vector.
Therefore substituting the value \[{{a}^{2}}=1\] in equation (1) , we get
\[ca-r=a\times b\]
We will now calculate the value of \[r\] by rearranging the terms of the above equation.
By taking vector \[r\] to the right and taking \[a\times b\] to the left side of the equation we get
\[ca-\left( a\times b \right)=r\]
Therefore the value of \[r\] is given by \[ca-\left( a\times b \right)\]
So, the correct answer is “Option (d)”.
Note: In this problem, we have also use the definition of cross product and dot product to get the
desired value of \[r\]. We have \[a\times b=ab\sin \theta \] where \[\theta \] is the angle between \[a\] and \[b\].
Also \[a\cdot b=ab\cos \theta \]. Then using the fact that \[a\cdot b=0\], we say that vectors \[a\] and \[b\] are orthogonal to each other. That is the vectors \[a\] and \[b\] are perpendicular to each other.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Assertion The resistivity of a semiconductor increases class 13 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
Using the following information to help you answer class 12 chemistry CBSE
Trending doubts
State the differences between manure and fertilize class 8 biology CBSE
Why are xylem and phloem called complex tissues aBoth class 11 biology CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
What would happen if plasma membrane ruptures or breaks class 11 biology CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
What precautions do you take while observing the nucleus class 11 biology CBSE
What would happen to the life of a cell if there was class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE