
If a capillary tube has been dipped in a liquid, the liquid will rise to a height $h$ in the tube. It has been given that the free liquid surface inside the tube will be hemispherical in the shape. The tube will be now pushed down so that the height of the tube outside the liquid will be less than $h$. Then,
This question will be having multiple correct options
A. The liquid has come out of the tube like in a small fountain.
B. The liquid will be oozing out of the tube slowly.
C. The liquid will fill the tube but not come out of its upper end.
D. The free liquid surface will not be hemispherical inside the tube.
Answer
484.8k+ views
Hint: The height to which the liquid will be rising can be found by taking the ratio of twice the product of the surface tension of the liquid and the cosine of the angle to the product of the radius of the liquid meniscus, the density and the acceleration due to gravity. This will help you in answering this question.
Complete answer:
First of all let us consider a capillary tube of radius $r$ which will be immersed in a liquid of surface tension $T$ and the density $\rho $. The height to which the liquid will be rising in the capillary tube has been given as,
$h=\dfrac{2T\cos \theta }{R\rho g}$
Where $T$ be the surface tension of the liquid, $R$ be the liquid meniscus, $\rho $ be the density and $g$ be the acceleration due to gravity. The angle will be perpendicular.
$h=\dfrac{2T\cos \theta }{R\rho g}=\dfrac{2T}{R\rho g}$
Rearranging this equation can be written as,
$hR=\dfrac{2T}{\rho g}$
This has been found to be a constant.
${{h}_{1}}{{R}_{1}}={{h}_{2}}{{R}_{2}}$
When the tube has been pushed down we are enhancing the $h$, thereby decreasing the radius $R$ of the liquid meniscus. Therefore as $h$ is increased, the level of the liquid becomes more and more flat but will not get overflowed. The angle of contact at the free liquid surface inside the capillary tube will be varying such that the vertical component of the surface tension forces will be balancing the weight of the liquid column.
Therefore the correct answers have been mentioned as option C and D.
Note:
Capillary action can be otherwise called as capillarity, capillary effect or wicking. This can be defined as the ability of a liquid to flow in the narrow spaces without the assistance of, or even in prevention to, external forces like gravity. It will be happening due to the intermolecular between the liquid and surrounding solid surfaces.
Complete answer:
First of all let us consider a capillary tube of radius $r$ which will be immersed in a liquid of surface tension $T$ and the density $\rho $. The height to which the liquid will be rising in the capillary tube has been given as,
$h=\dfrac{2T\cos \theta }{R\rho g}$
Where $T$ be the surface tension of the liquid, $R$ be the liquid meniscus, $\rho $ be the density and $g$ be the acceleration due to gravity. The angle will be perpendicular.
$h=\dfrac{2T\cos \theta }{R\rho g}=\dfrac{2T}{R\rho g}$
Rearranging this equation can be written as,
$hR=\dfrac{2T}{\rho g}$
This has been found to be a constant.
${{h}_{1}}{{R}_{1}}={{h}_{2}}{{R}_{2}}$
When the tube has been pushed down we are enhancing the $h$, thereby decreasing the radius $R$ of the liquid meniscus. Therefore as $h$ is increased, the level of the liquid becomes more and more flat but will not get overflowed. The angle of contact at the free liquid surface inside the capillary tube will be varying such that the vertical component of the surface tension forces will be balancing the weight of the liquid column.
Therefore the correct answers have been mentioned as option C and D.
Note:
Capillary action can be otherwise called as capillarity, capillary effect or wicking. This can be defined as the ability of a liquid to flow in the narrow spaces without the assistance of, or even in prevention to, external forces like gravity. It will be happening due to the intermolecular between the liquid and surrounding solid surfaces.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Draw a labelled sketch of the human eye class 12 physics CBSE

a Tabulate the differences in the characteristics of class 12 chemistry CBSE

Which one of the following is a true fish A Jellyfish class 12 biology CBSE

Why is the cell called the structural and functional class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Write the difference between solid liquid and gas class 12 chemistry CBSE
