
If $20.00moles$ of calcium reacted, how many grams of calcium oxide are produced?
Answer
548.1k+ views
Hint:To solve this question, we can use the concept of stoichiometry. Stoichiometry can be defined as a branch of chemistry that involves using the relationships between reactants or products in a chemical reaction to obtain the desired quantitative data. Stoichiometric coefficient is the number which is written in front of the atoms, ions, or molecules in a chemical reaction in order to balance the number of each element on both sides of the equation.
Complete step-by-step answer: As we know the balanced chemical equation for the production of calcium oxide from calcium can be written as
\[2Ca + {O_2} \to 2CaO\]
This equation says that for every two moles of calcium two moles of calcium oxide is being produced.
The molar mass of CaO is \[40.078 + 15.999 = 56.077g\]
Since we have to find grams of calcium oxide from $20moles$of calcium , we first need to find moles of calcium oxide that is produced then convert it to grams of calcium oxide.
Hence, equation to find out grams of calcium oxide produced from $20moles$ of calcium is given by,
$20mol{\text{ Calcium}} \times \dfrac{{2molCaO}}{{2mol{\text{ calcium}}}} \times \dfrac{{56.077g{\text{ }}CaO}}{{1mol{\text{ }}CaO}} = 1121.54g{\text{ CaO}}$
Additional information:The most common type of stoichiometric relationship is the mole ratio. It relates the amounts in moles of any two substances in a chemical reaction. We can write a mole ratio for a pair of substances by looking at the coefficients in front of each species in the given balanced chemical equation.
Note:Stoichiometry is based on the law of conservation of mass where the total mass of the reactants is equal to the total mass of the products, which means that the relations among quantities of reactants and products form a ratio of positive integers. Hence, we can say that, if the amounts of the separate reactants are known, then the amount of the product can be calculated.
Complete step-by-step answer: As we know the balanced chemical equation for the production of calcium oxide from calcium can be written as
\[2Ca + {O_2} \to 2CaO\]
This equation says that for every two moles of calcium two moles of calcium oxide is being produced.
The molar mass of CaO is \[40.078 + 15.999 = 56.077g\]
Since we have to find grams of calcium oxide from $20moles$of calcium , we first need to find moles of calcium oxide that is produced then convert it to grams of calcium oxide.
Hence, equation to find out grams of calcium oxide produced from $20moles$ of calcium is given by,
$20mol{\text{ Calcium}} \times \dfrac{{2molCaO}}{{2mol{\text{ calcium}}}} \times \dfrac{{56.077g{\text{ }}CaO}}{{1mol{\text{ }}CaO}} = 1121.54g{\text{ CaO}}$
Additional information:The most common type of stoichiometric relationship is the mole ratio. It relates the amounts in moles of any two substances in a chemical reaction. We can write a mole ratio for a pair of substances by looking at the coefficients in front of each species in the given balanced chemical equation.
Note:Stoichiometry is based on the law of conservation of mass where the total mass of the reactants is equal to the total mass of the products, which means that the relations among quantities of reactants and products form a ratio of positive integers. Hence, we can say that, if the amounts of the separate reactants are known, then the amount of the product can be calculated.
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