
Identify the least stable ion amongst the following:
A.$L{i^ - }$
B.$B{e^ - }$
C.${B^ - }$
D.${C^ - }$
Answer
554.1k+ views
Hint:This question gives the knowledge about periodic table and electronic configuration. Periodic table is basically the tabular representation of elements, which are organized by electronic configuration, atomic number and repeated chemical properties. The elements which are present in the same group experience the same electronic configuration in the valence shell.
Complete answer:
The electronic configuration is a way of representing the arrangement of electrons in the orbitals. The electronic configuration of $B{e^ - }$ is $1{s^2}2{s^2}2{p^1}$. Beryllium is an element of the second group whose valence electron enters in the s-orbital but here the valence electron enters the p-orbital due to which $B{e^ - }$ loses its identity and becomes unstable.
Therefore, option $B$ is the correct option.
Note:
Periodic table is basically the tabular representation of elements, which are organized by electronic configuration, atomic number and repeated chemical properties. Periodic table consists of seven rows and eighteen groups. In rows, the elements are organized from left to right and in groups, elements are organized from top to bottom. In total there are $118$ elements present in the periodic table.
The number of protons present in the nucleus determines the atomic number.
Properties of periodic table are as follows:
$1$. The elements which are present in the same group experience the same electronic configuration in the valence shell.
$2$. The elements which are present in the same group experience similar chemical properties.
$3$. The elements which are present in the same period experiences increase in valence electrons.
$4$. The elements which are present in the same period experiences increase in the number of energy subshells.
$5$. In the periodic table, ionization energy decreases the group.
$6$. In the periodic table, electronegativity decreases the group.
$7$. In the periodic table, atomic radii increases the group.
Complete answer:
The electronic configuration is a way of representing the arrangement of electrons in the orbitals. The electronic configuration of $B{e^ - }$ is $1{s^2}2{s^2}2{p^1}$. Beryllium is an element of the second group whose valence electron enters in the s-orbital but here the valence electron enters the p-orbital due to which $B{e^ - }$ loses its identity and becomes unstable.
Therefore, option $B$ is the correct option.
Note:
Periodic table is basically the tabular representation of elements, which are organized by electronic configuration, atomic number and repeated chemical properties. Periodic table consists of seven rows and eighteen groups. In rows, the elements are organized from left to right and in groups, elements are organized from top to bottom. In total there are $118$ elements present in the periodic table.
The number of protons present in the nucleus determines the atomic number.
Properties of periodic table are as follows:
$1$. The elements which are present in the same group experience the same electronic configuration in the valence shell.
$2$. The elements which are present in the same group experience similar chemical properties.
$3$. The elements which are present in the same period experiences increase in valence electrons.
$4$. The elements which are present in the same period experiences increase in the number of energy subshells.
$5$. In the periodic table, ionization energy decreases the group.
$6$. In the periodic table, electronegativity decreases the group.
$7$. In the periodic table, atomic radii increases the group.
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