
Hydrogen peroxide is prepared in the laboratory by :
\[{\text{(A)}}\] Adding \[{\text{Mn}}{{\text{O}}_{\text{2}}}\] to dilute \[{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\]
\[{\text{(B)}}\]Passing \[{\text{C}}{{\text{O}}_{\text{2}}}\] into \[{\text{Ba}}{{\text{O}}_{\text{2}}}\] paste in cold water
\[{\text{(C)}}\]Adding \[{\text{Pb}}{{\text{O}}_{\text{2}}}\] to an acidified \[{\text{KMn}}{{\text{O}}_{\text{4}}}\] solution
\[{\text{(D)}}\]Adding \[{\text{N}}{{\text{a}}_{\text{2}}}{{\text{O}}_{\text{2}}}\] to cold water
Answer
585.6k+ views
Hint:Hydrogen peroxide is an oxidizing agent useful for synthetic purposes and also catalyze many reactions. it may be prepared from following methods:
1.From barium peroxide
2.From electrolytic process
3.From non-electrolytic process.
Complete step by step answer:
Preparation of hydrogen peroxide \[{\text{(}}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}})\]:
We can prepare hydrogen peroxide by the action of \[{\text{C}}{{\text{O}}_{\text{2}}}\] on Barium peroxide. Here we use a thick icy paste of barium hydroxide by putting in some ice cold water and we pass \[{\text{C}}{{\text{O}}_{\text{2}}}\] to the thick icy paste of barium hydroxide. Now \[{\text{C}}{{\text{O}}_{\text{2}}}\] on reaction with water is generates carbonic acid \[{\text{(}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}{\text{)}}\] and then \[{\text{Ba}}{{\text{O}}_{\text{2}}}\] reacts with \[{{\text{H}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\] to form barium carbonate and it is obtained as a white precipitate which can be removed by filtration, hydrogen peroxide is left behind as a byproduct.
\[{\text{Ba}}{{\text{O}}_{\text{2}}}{\text{ + C}}{{\text{O}}_{\text{2}}}{\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}} \to {\text{BaC}}{{\text{O}}_{\text{3}}}{\text{ + }}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}\]
Therefore, the correct answer is option \[{\text{(B)}}\].
Additional information:
Hydrogen peroxide can be prepared by the action of sulphuric acid or phosphoric acid on hydrated barium peroxide \[{\text{Ba}}{{\text{O}}_{\text{2}}}{\text{.8}}{{\text{H}}_{\text{2}}}{\text{O}}\].
\[{\text{Ba}}{{\text{O}}_{\text{2}}}{\text{.8}}{{\text{H}}_{\text{2}}}{\text{O (s) + }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}{\text{(aq)}} \to {\text{BaS}}{{\text{O}}_{\text{4}}}{\text{(s) + }}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}{\text{(aq) + 8}}{{\text{H}}_{\text{2}}}{\text{O (l)}}\]
Anhydrous barium peroxide do not readily react with \[{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\] as a coating of the insoluble barium sulphate is generated on its surface that further stops action of the acid. Therefore, hydrated barium peroxide i.e. \[{\text{Ba}}{{\text{O}}_{\text{2}}}{\text{.8}}{{\text{H}}_{\text{2}}}{\text{O}}\] should be used . The product of the barium sulphate is obtained in the form of white precipitate so that it become easy for us for filtering out the precipitate and the we get a solution of \[{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}\].
Note:
Hydrogen peroxide prepared from barium peroxide and sulfuric acid can't be used for a longer duration of time or can’t be stored for a long time. So what we do is instead of using sulphuric acid we use phosphoric acid. The reaction can be given as,
\[{\text{3Ba}}{{\text{O}}_{\text{2}}}{\text{.8}}{{\text{H}}_{\text{2}}}{\text{O + 2}}{{\text{H}}_{\text{3}}}{\text{P}}{{\text{O}}_{\text{4}}} \to {\text{B}}{{\text{a}}_{\text{3}}}{{\text{(P}}{{\text{O}}_{\text{4}}}{\text{)}}_{\text{2}}}{\text{ + 3}}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}{\text{ + 24}}{{\text{H}}_{\text{2}}}{\text{O}}\]
1.From barium peroxide
2.From electrolytic process
3.From non-electrolytic process.
Complete step by step answer:
Preparation of hydrogen peroxide \[{\text{(}}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}})\]:
We can prepare hydrogen peroxide by the action of \[{\text{C}}{{\text{O}}_{\text{2}}}\] on Barium peroxide. Here we use a thick icy paste of barium hydroxide by putting in some ice cold water and we pass \[{\text{C}}{{\text{O}}_{\text{2}}}\] to the thick icy paste of barium hydroxide. Now \[{\text{C}}{{\text{O}}_{\text{2}}}\] on reaction with water is generates carbonic acid \[{\text{(}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}{\text{)}}\] and then \[{\text{Ba}}{{\text{O}}_{\text{2}}}\] reacts with \[{{\text{H}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\] to form barium carbonate and it is obtained as a white precipitate which can be removed by filtration, hydrogen peroxide is left behind as a byproduct.
\[{\text{Ba}}{{\text{O}}_{\text{2}}}{\text{ + C}}{{\text{O}}_{\text{2}}}{\text{ + }}{{\text{H}}_{\text{2}}}{\text{O}} \to {\text{BaC}}{{\text{O}}_{\text{3}}}{\text{ + }}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}\]
Therefore, the correct answer is option \[{\text{(B)}}\].
Additional information:
Hydrogen peroxide can be prepared by the action of sulphuric acid or phosphoric acid on hydrated barium peroxide \[{\text{Ba}}{{\text{O}}_{\text{2}}}{\text{.8}}{{\text{H}}_{\text{2}}}{\text{O}}\].
\[{\text{Ba}}{{\text{O}}_{\text{2}}}{\text{.8}}{{\text{H}}_{\text{2}}}{\text{O (s) + }}{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}{\text{(aq)}} \to {\text{BaS}}{{\text{O}}_{\text{4}}}{\text{(s) + }}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}{\text{(aq) + 8}}{{\text{H}}_{\text{2}}}{\text{O (l)}}\]
Anhydrous barium peroxide do not readily react with \[{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}\] as a coating of the insoluble barium sulphate is generated on its surface that further stops action of the acid. Therefore, hydrated barium peroxide i.e. \[{\text{Ba}}{{\text{O}}_{\text{2}}}{\text{.8}}{{\text{H}}_{\text{2}}}{\text{O}}\] should be used . The product of the barium sulphate is obtained in the form of white precipitate so that it become easy for us for filtering out the precipitate and the we get a solution of \[{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}\].
Note:
Hydrogen peroxide prepared from barium peroxide and sulfuric acid can't be used for a longer duration of time or can’t be stored for a long time. So what we do is instead of using sulphuric acid we use phosphoric acid. The reaction can be given as,
\[{\text{3Ba}}{{\text{O}}_{\text{2}}}{\text{.8}}{{\text{H}}_{\text{2}}}{\text{O + 2}}{{\text{H}}_{\text{3}}}{\text{P}}{{\text{O}}_{\text{4}}} \to {\text{B}}{{\text{a}}_{\text{3}}}{{\text{(P}}{{\text{O}}_{\text{4}}}{\text{)}}_{\text{2}}}{\text{ + 3}}{{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}{\text{ + 24}}{{\text{H}}_{\text{2}}}{\text{O}}\]
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

