
Hydrochloric acid (\[HCl\]) does not behave as the acid in __
A.$N{H_3}$
B.${C_2}{H_5}OH$
C.${H_2}O$
D.${C_6}{H_6}$
Answer
558.9k+ views
Hint: In the given question firstly we have to define why exactly the \[HCl\] don’t show ionic character in any one of them. Now after that, we have the reason that the solubility is due to the ionic nature of the water and the polarity of the water. As we know being a covalent compound the ionic nature is missing from the Benzene and that it has no polarity in its structure. Now that makes the case for non-acidic nature.
Complete step by step solution:
In the given question we have to first find out the nature of the \[HCl\] in the given compounds when they are treated as a solvent. This is because to show the ionic nature it is important for a compound to further dissolve into its constituent ions in a particular paradigm.
So here we have to deal with the concept of dissolution, as basically the question asked by the statement is regarding the inability of \[HCl\] to behave like acid in one of the given solvents.
Now firstly we need to know the nature of all the components involved in the question. In the question there is the presence of only one solute that is \[HCl\] which is also highly ionic in nature.
The process of dissolution of the \[HCl\] involves the breakage of the ionic bond in order to form the ions and that is fulfilled by water due to two factors. First that it is ionic in nature which provides an excellent solvent for the ionic \[HCl\]. Now the other factor is the polarity which leads to the dissolution.
In the case of Benzene (${C_6}{H_6}$ ) both these factors are missing as it is non-ionic in nature and not polarising in nature too.
And according to the principle of "like dissolve like '', we can say that the ionic solvent needs the ionic solute and the nonionic needs non-ionic.
Thus we can say that \[HCl\] will not show its ionic properties in the ${C_6}{H_6}$.
Therefore, the right option is the option D.
Note: The reason why all the non-polar molecules have the capability to dissolve in nonpolar substances is because of the fact that there is no need to compete with the attraction between any of the molecules because there essentially isn’t any. Now, apart from that, the other reason why polar solutes typically do not dissolve in non-polar solvents is that there is nothing to keep the polar and nonpolar molecules near each due to the absence of the attraction forces.
Complete step by step solution:
In the given question we have to first find out the nature of the \[HCl\] in the given compounds when they are treated as a solvent. This is because to show the ionic nature it is important for a compound to further dissolve into its constituent ions in a particular paradigm.
So here we have to deal with the concept of dissolution, as basically the question asked by the statement is regarding the inability of \[HCl\] to behave like acid in one of the given solvents.
Now firstly we need to know the nature of all the components involved in the question. In the question there is the presence of only one solute that is \[HCl\] which is also highly ionic in nature.
The process of dissolution of the \[HCl\] involves the breakage of the ionic bond in order to form the ions and that is fulfilled by water due to two factors. First that it is ionic in nature which provides an excellent solvent for the ionic \[HCl\]. Now the other factor is the polarity which leads to the dissolution.
In the case of Benzene (${C_6}{H_6}$ ) both these factors are missing as it is non-ionic in nature and not polarising in nature too.
And according to the principle of "like dissolve like '', we can say that the ionic solvent needs the ionic solute and the nonionic needs non-ionic.
Thus we can say that \[HCl\] will not show its ionic properties in the ${C_6}{H_6}$.
Therefore, the right option is the option D.
Note: The reason why all the non-polar molecules have the capability to dissolve in nonpolar substances is because of the fact that there is no need to compete with the attraction between any of the molecules because there essentially isn’t any. Now, apart from that, the other reason why polar solutes typically do not dissolve in non-polar solvents is that there is nothing to keep the polar and nonpolar molecules near each due to the absence of the attraction forces.
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