
How many hybrid orbitals are present in the molecule \[PC{l_5}\]?
Answer
556.8k+ views
Hint: The concept of hybridization is based on VSEPR theory. The VSEPR theory says that during a bond formation mixing of orbitals takes place.
Complete step by step answer:
The given compound is phosphorus pentachloride. It is an inorganic compound composed of phosphorus and chlorine atoms. Phosphorus is the least electronegative atom between phosphorus and chlorine, so it is the central atom according to VSEPR theory.
Phosphorus is an element in the periodic table with atomic number \[15\] and electronic configuration \[\left[ {Ne} \right]3{s^2}3{p^3}\]. The outermost shell of phosphorus is \[3\] which has five electrons of which two electrons are present in \[3s\]-orbital and three electrons are present in \[3p\]-orbital. Phosphorus also has outer \[3d\]-orbitals which are used for bond formation.
In \[PC{l_5}\], five \[P - Cl\] bonds are present so the \[P\] atom needs five orbitals to form the five \[P - Cl\] bonds. In order to form five bonds the \[P\] atom needs one \[3s\] and three \[3p\] orbitals and one \[3d\] orbital. The hybridization of the \[P\] atom is \[s{p^3}d\]. This is also evaluated using the VSEP number.
VSEPR number = $\dfrac{1}{2}$ (number of electrons from \[P\] atom + number of bonded \[Cl\] atoms)
$ = \dfrac{1}{2}(5 + 5) = 5.$
The VSEP number equal to \[5\] belongs to \[s{p^3}d\] hybridization. Thus the geometry of the molecule is trigonal bipyramidal. Three chlorine atoms are positioned in the equatorial positions and two chlorine atoms are positioned in two axial positions of the TBP structure.
Thus all the hybridized orbitals of phosphorus atoms are used up in \[PC{l_5}\] and no hybrid orbitals remain free.
Note:
The concept of hybridization is very helpful in the determination of molecular structures of several molecules. The VSEPR is the short form of Valence Shell Electron Pair Repulsion Theory. The interactions between the bond pairs and lone pairs of electrons are considered for obtaining the exact structure.
Complete step by step answer:
The given compound is phosphorus pentachloride. It is an inorganic compound composed of phosphorus and chlorine atoms. Phosphorus is the least electronegative atom between phosphorus and chlorine, so it is the central atom according to VSEPR theory.
Phosphorus is an element in the periodic table with atomic number \[15\] and electronic configuration \[\left[ {Ne} \right]3{s^2}3{p^3}\]. The outermost shell of phosphorus is \[3\] which has five electrons of which two electrons are present in \[3s\]-orbital and three electrons are present in \[3p\]-orbital. Phosphorus also has outer \[3d\]-orbitals which are used for bond formation.
In \[PC{l_5}\], five \[P - Cl\] bonds are present so the \[P\] atom needs five orbitals to form the five \[P - Cl\] bonds. In order to form five bonds the \[P\] atom needs one \[3s\] and three \[3p\] orbitals and one \[3d\] orbital. The hybridization of the \[P\] atom is \[s{p^3}d\]. This is also evaluated using the VSEP number.
VSEPR number = $\dfrac{1}{2}$ (number of electrons from \[P\] atom + number of bonded \[Cl\] atoms)
$ = \dfrac{1}{2}(5 + 5) = 5.$
The VSEP number equal to \[5\] belongs to \[s{p^3}d\] hybridization. Thus the geometry of the molecule is trigonal bipyramidal. Three chlorine atoms are positioned in the equatorial positions and two chlorine atoms are positioned in two axial positions of the TBP structure.
Thus all the hybridized orbitals of phosphorus atoms are used up in \[PC{l_5}\] and no hybrid orbitals remain free.
Note:
The concept of hybridization is very helpful in the determination of molecular structures of several molecules. The VSEPR is the short form of Valence Shell Electron Pair Repulsion Theory. The interactions between the bond pairs and lone pairs of electrons are considered for obtaining the exact structure.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

