
How do you solve $ p = 2l + 2w $ for $ l $ ?
Answer
516.3k+ views
Hint: In order to solve $ p = 2l + 2w $ for $ l $ just move the constants and not needed part form right to left except $ l $ . First subtract $ 2w $ from both the sides, then to obtain $ l $ , as a single variable on one side divide both the sides by $ 2 $ .
Complete step by step solution:
The Equation given is $ p = 2l + 2w $ .
We have to solve for $ l $ from the given equation. Basically, we have to separate $ l $ on the right side by multiplying or dividing the constants.
So, let’s start with the first step:
Subtracting both sides by $ 2w $ to cut out $ 2w $ or move $ 2w $ from the right to left side and we get:
$
p = 2l + 2w \\
p - 2w = 2l \;
$
Now, we are left with $ 2 $ and $ l $ , we have to remove $ 2 $ so that we are left with our needed value or result that is only $ l $ .
For the second step, divide both the sides by $ 2 $ to get only $ l $ alone on the right side and no other constants with it and we get:
$
\Rightarrow p = 2l + 2w \\
\Rightarrow p - 2w = 2l \\
\Rightarrow \dfrac{{p - 2w}}{2} = \dfrac{{2l}}{2} \\
\Rightarrow \dfrac{{p - 2w}}{2} = l \;
$
Therefore, the value of $ l $ in $ p = 2w + 2l $ is \[l = \dfrac{{p - 2w}}{2}\].
So, the correct answer is “\[l = \dfrac{{p - 2w}}{2}\]”.
Note: There is nothing in this question just moving of constants to get the value of $ l $ so, don’t try to put up the formulas or values which would complicate the steps.
Don’t leave $ 2l $ as it is because we want the value of only $ l $ and not of $ 2l $ , which could change the answer.
If instead of $ l $ , we had to find any other values then this process was only followed but with slight changes in the subtraction and division parts.
Complete step by step solution:
The Equation given is $ p = 2l + 2w $ .
We have to solve for $ l $ from the given equation. Basically, we have to separate $ l $ on the right side by multiplying or dividing the constants.
So, let’s start with the first step:
Subtracting both sides by $ 2w $ to cut out $ 2w $ or move $ 2w $ from the right to left side and we get:
$
p = 2l + 2w \\
p - 2w = 2l \;
$
Now, we are left with $ 2 $ and $ l $ , we have to remove $ 2 $ so that we are left with our needed value or result that is only $ l $ .
For the second step, divide both the sides by $ 2 $ to get only $ l $ alone on the right side and no other constants with it and we get:
$
\Rightarrow p = 2l + 2w \\
\Rightarrow p - 2w = 2l \\
\Rightarrow \dfrac{{p - 2w}}{2} = \dfrac{{2l}}{2} \\
\Rightarrow \dfrac{{p - 2w}}{2} = l \;
$
Therefore, the value of $ l $ in $ p = 2w + 2l $ is \[l = \dfrac{{p - 2w}}{2}\].
So, the correct answer is “\[l = \dfrac{{p - 2w}}{2}\]”.
Note: There is nothing in this question just moving of constants to get the value of $ l $ so, don’t try to put up the formulas or values which would complicate the steps.
Don’t leave $ 2l $ as it is because we want the value of only $ l $ and not of $ 2l $ , which could change the answer.
If instead of $ l $ , we had to find any other values then this process was only followed but with slight changes in the subtraction and division parts.
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