
How do you solve $\left| {t + 4} \right| > 10$ ?
Answer
544.5k+ views
Hint: In this question, we need to solve the given inequality with absolute value. Firstly, we will define the general definition of modulus or absolute value and then we will define it in terms of the given problem. Then we find the solution to the problem for $t < - 4$ and $t \geqslant - 4$. After that we simplify and obtain the required solution.
Complete step by step answer:
Given $\left| {t + 4} \right| > 10$
We are asked to solve the above inequality.
Note that this is an inequality with absolute value, so we can solve it directly.
Firstly, we will give the general definition of absolute value.
For any real number x, the absolute value or modulus denoted by $\left| x \right|$ of x is defined as,
If $x \geqslant 0$, then $\left| x \right| = x$
If $\left| x \right| < 0$, then $\left| x \right| = - x$
Now we apply this definition to $\left| {t + 4} \right|$.
If $t \geqslant - 4,$ then $\left| {t + 4} \right| = t + 4$
If $t < - 4,$ then $\left| {t + 4} \right| = - (t + 4) = - t - 4$
So to solve $\left| {t + 4} \right| > 10$, we need to consider two cases.
Case (1) : If $t \geqslant - 4,$ we have,
$ \Rightarrow t + 4 > 10$
Subtracting 4 from both sides of the inequality we get,
$ \Rightarrow t + 4 - 4 > 10 - 4$
$ \Rightarrow t + 0 > 6$
$ \Rightarrow t > 6$
Case (2) : If $t < - 4,$ we have,
$ \Rightarrow - t - 4 > 10$
Adding 4 on both sides of the inequality we get,
$ \Rightarrow - t - 4 + 4 > 10 + 4$
$ \Rightarrow - t + 0 > 14$
$ \Rightarrow - t > 14$
Multiplying by -1 on both sides of the inequality, we get,
$ \Rightarrow t < - 14$
Note that when we multiply by a negative number the inequality reverses.
So finally we have, $6 < t $ and $ t < - 14$.
Thus, by solving $\left| {t + 4} \right| > 10$, we get $6 < t $ and $ t < - 14$.
Note: Students must know the definition of modulus or absolute value.
For any real number x, the absolute value or modulus denoted by $\left| x \right|$ of x is defined as,
If $x \geqslant 0$, then $\left| x \right| = x$
If $\left| x \right| < 0$, then $\left| x \right| = - x$
The absolute value of x is always either positive or zero, but never negative.
Also we must know how to use this definition to a given problem and simplify it. This is more important.
Complete step by step answer:
Given $\left| {t + 4} \right| > 10$
We are asked to solve the above inequality.
Note that this is an inequality with absolute value, so we can solve it directly.
Firstly, we will give the general definition of absolute value.
For any real number x, the absolute value or modulus denoted by $\left| x \right|$ of x is defined as,
If $x \geqslant 0$, then $\left| x \right| = x$
If $\left| x \right| < 0$, then $\left| x \right| = - x$
Now we apply this definition to $\left| {t + 4} \right|$.
If $t \geqslant - 4,$ then $\left| {t + 4} \right| = t + 4$
If $t < - 4,$ then $\left| {t + 4} \right| = - (t + 4) = - t - 4$
So to solve $\left| {t + 4} \right| > 10$, we need to consider two cases.
Case (1) : If $t \geqslant - 4,$ we have,
$ \Rightarrow t + 4 > 10$
Subtracting 4 from both sides of the inequality we get,
$ \Rightarrow t + 4 - 4 > 10 - 4$
$ \Rightarrow t + 0 > 6$
$ \Rightarrow t > 6$
Case (2) : If $t < - 4,$ we have,
$ \Rightarrow - t - 4 > 10$
Adding 4 on both sides of the inequality we get,
$ \Rightarrow - t - 4 + 4 > 10 + 4$
$ \Rightarrow - t + 0 > 14$
$ \Rightarrow - t > 14$
Multiplying by -1 on both sides of the inequality, we get,
$ \Rightarrow t < - 14$
Note that when we multiply by a negative number the inequality reverses.
So finally we have, $6 < t $ and $ t < - 14$.
Thus, by solving $\left| {t + 4} \right| > 10$, we get $6 < t $ and $ t < - 14$.
Note: Students must know the definition of modulus or absolute value.
For any real number x, the absolute value or modulus denoted by $\left| x \right|$ of x is defined as,
If $x \geqslant 0$, then $\left| x \right| = x$
If $\left| x \right| < 0$, then $\left| x \right| = - x$
The absolute value of x is always either positive or zero, but never negative.
Also we must know how to use this definition to a given problem and simplify it. This is more important.
Recently Updated Pages
Complete reduction of benzene diazonium chloride with class 12 chemistry CBSE

How can you identify optical isomers class 12 chemistry CBSE

The coating formed on the metals such as iron silver class 12 chemistry CBSE

Metals are refined by using different methods Which class 12 chemistry CBSE

What do you understand by denaturation of proteins class 12 chemistry CBSE

Assertion Nitrobenzene is used as a solvent in FriedelCrafts class 12 chemistry CBSE

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

RNA and DNA are chiral molecules their chirality is class 12 chemistry CBSE

