Question

How do you solve $\dfrac{1}{3}x > 6?$

Answer 1

Hint: Here we are given greater than inequality pattern and so first of all we will clear the absolute value and accordingly follow the greater than pattern. Will simplify the equations using the basic concepts and will find the value for the unknown term “x”.

Complete step-by-step solution:
Take the given expression: $\dfrac{1}{3}x > 6$
Multiply with on both the sides of the equation.
$3 \times \dfrac{1}{3}x > 3 \times 6$
Simplify the above equation considering that the Common factor from the numerator and the denominator cancels each other. Therefore, remove from the numerator and the denominator on the left hand side of the expression.
$x > 3 \times 6$
Find the product for the term on the right hand side of the equation.
$x > 18$
This is the required solution.

Hence the solution for the given question is $x > 18$

Additional information:Be careful about the sign while doing simplification remember the golden rules-
-Addition of two positive terms gives the positive term
-Addition of one negative and positive term, you have to do subtraction and give signs of bigger numbers whether positive or negative.
-Addition of two negative numbers gives a negative number but in actual you have to add both the numbers and give a negative sign to the resultant answer.

Note: Always remember when you add /subtract /multiply /divide any number on one side of the equation, its value gets changes so for the equivalent value you always have to perform any changes similar on both the sides of the equation to keep the equivalent value of the original equation. Also, remember you can do addition and subtraction of the same value on one side as addition and subtraction of the same value cancel each other and ultimately value remains the same. The same way multiplication and division of the same number cancels each other.