Question

How do you solve \[7a-3=3+6a\]?

Answer 1

Hint: we can solve this using a simple linear equation concept. First we have to make all the like terms one side and then we have to solve for the value a. So first we will take terms containing variables a to one side and other on the other side. Then we will simplify to get the answer.

Complete step-by-step solution:
Given equation is
\[7a-3=3+6a\]
First we have to make terms on one side. For this we have to take all the terms containing a on one side.
So we will subtract \[6a\] from both sides of the equation.
We will get
\[\Rightarrow 7a-3-6a=3+6a-6a\]
By subtracting the like terms we will get
\[\Rightarrow a-3=3\]
Now we have to simplify the equation to get the answer.
To find the value of a we have to add 3 on both sides of the equation.
By adding 3 we will get
\[\Rightarrow a-3+3=3+3\]
Now we have to add or subtract the values accordingly to get the answer.
\[\Rightarrow a=6\]
Now we can say that by simplifying the given equation we will get the value of a as \[6\]
\[a=6\]

Note: we can also check the answer by back substituting the value in the equation.
We can do it by substituting the value \[6\] in the given equation.
By substituting \[6\] in the given equation we will get
\[\Rightarrow 7\left( 6 \right)-3=3+6\left( 6 \right)\]
Now we have to simplify both RHS and LHS to verify the equation. We have to obtain the same value on both the RHS and LHS side.
By simplifying it we will get
\[\Rightarrow 42-3=3+36\]
\[\Rightarrow 39=39\]
So we have got the same value on both the RHS and LHS side so our answer is verified.