Question

How do you solve $ 6x - 4 = 3x + 2 $ ?

Answer 1

Hint: n order to determine the value of variable $ x $ in the above equation. Combining like terms by Using the rules of transposing terms to transpose terms having $ x $ on the left-hand side and constant value terms on the right-Hand side of the equation. Combine and solve like terms and divide the equation with coefficient of $ x $ to get your desired solution.

Complete step by step solution:
 We are given a linear equation in one variable $ 6x - 4 = 3x + 2 $ .and we have to solve this equation for variable ( $ x $ ).
 $ 6x - 4 = 3x + 2 $
Now combining like terms on both of the sides. Terms having $ x $ will on the left-Hand side of the equation and constant terms on the right-hand side.
Let’s recall one basic property of transposing terms that on transposing any term from one side to another the sign of that term get reversed .
After transposing terms our equation becomes
 $ 6x - 3x = 2 + 4 $
Solving all the like term by resolving the operators,
 $ 3x = 6 $
Dividing both sides of the equation with the coefficient of $ x $ i.e. $ 3 $ , we obtain the value of $ x $ as
 $
\Rightarrow \dfrac{{3x}}{3} = \dfrac{6}{3} \\
\Rightarrow x = 2 \;
  $
Therefore, the solution to the given equation is equal to $ x = 2 $ .
So, the correct answer is “ $ x = 2 $ .”.

Note: Linear Equation in one variable: A linear equation is a equation which can be represented in the form of $ ax + c $ where $ x $ is the unknown variable and a,c are the numbers known where $ a \ne 0 $ .If $ a = 0 $ then the equation will become constant value and will no more be a linear equation .
The degree of the variable in the linear equation is of the order 1.
Every Linear equation has 1 root.