
How do you solve $5 - x = 16$?
Answer
558k+ views
Hint: Here we will use different mathematical operations here to solve it. First, we will subtract the number from both sides of the equation and then we will divide both sides by the number which is multiplied with the variable. After simplification, we will get the required value of the variable.
Complete step by step solution:
We need to find the value of the variable used in the given algebraic equation.
$5 - x = 16$.
We will first subtract 5 from both sides of the algebraic equation.
$ \Rightarrow 5 - x - 5 = 16 - 5$
On further simplification, we get
$ \Rightarrow - x = 11$
Now, we will multiply $ - 1$ to both sides of the algebraic equation.
$ \Rightarrow \left( { - 1} \right) \times \left( { - x} \right) = \left( { - 1} \right) \times 11$
On further simplifying the terms, we get
$ \Rightarrow x = - 11$
Therefore, the value of the required variable used in the algebraic equation is equal to $ - 11$ and hence, this is the required solution of the given algebraic equation.
Additional information:
There are many types of algebraic equations such as quadratic equations, cubic equations, etc. A quadratic equation is an equation that has the highest degree of 2 and also has two solutions. Similarly, a cubic equation is an equation that has the highest degree of 3 and has 3 solutions. So, we can say that the number of solutions of an equation depends on the highest degree of the equation.
Note: Here we have obtained the required value of the variable used in the algebraic equation. The algebraic equation used in the question is a linear algebraic equation because the degree of the equation is 1. We have also used various mathematical operations to solve the given algebraic equation. So we need to remember that when we multiply two negative numbers together then the resultant value will be a positive number.
Complete step by step solution:
We need to find the value of the variable used in the given algebraic equation.
$5 - x = 16$.
We will first subtract 5 from both sides of the algebraic equation.
$ \Rightarrow 5 - x - 5 = 16 - 5$
On further simplification, we get
$ \Rightarrow - x = 11$
Now, we will multiply $ - 1$ to both sides of the algebraic equation.
$ \Rightarrow \left( { - 1} \right) \times \left( { - x} \right) = \left( { - 1} \right) \times 11$
On further simplifying the terms, we get
$ \Rightarrow x = - 11$
Therefore, the value of the required variable used in the algebraic equation is equal to $ - 11$ and hence, this is the required solution of the given algebraic equation.
Additional information:
There are many types of algebraic equations such as quadratic equations, cubic equations, etc. A quadratic equation is an equation that has the highest degree of 2 and also has two solutions. Similarly, a cubic equation is an equation that has the highest degree of 3 and has 3 solutions. So, we can say that the number of solutions of an equation depends on the highest degree of the equation.
Note: Here we have obtained the required value of the variable used in the algebraic equation. The algebraic equation used in the question is a linear algebraic equation because the degree of the equation is 1. We have also used various mathematical operations to solve the given algebraic equation. So we need to remember that when we multiply two negative numbers together then the resultant value will be a positive number.
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