How do you solve \[4(4 - w) = 3(2w + 2)\] ?
Answer
598.5k+ views
Hint: In the given problem we need to solve this for ‘w’. We can solve this using the transposition method. The common transposition method is to do the same thing (mathematically) to both sides of the equation, with the aim of bringing like terms together and isolating the variable (or the unknown quantity). That is we group the ‘x’ terms one side and constants on the other side of the equation.
Complete step by step solution:
Given, \[4(4 - w) = 3(2w + 2)\] .
Expanding the brackets we have,
\[16 - 4w = 6w + 6\]
We transpose \[16\] which is present in the left hand side of the equation to the right hand side of the equation by subtracting \[16\] on the right hand side of the equation.
\[ - 4w = 6w + 6 - 16\]
We transpose \[6w\] to the right hand side of the equation by subtracting \[6w\] on the right hand side of the equation.
\[ - 6w - 4w = 6 - 16\]
\[ - 10w = - 10\]
Divide the whole equation by \[ - 10\] .
\[w = \dfrac{{ - 10}}{{ - 10}}\]
\[ \Rightarrow w = 1\] is the required answer.
So, the correct answer is “w = 1”.
Note: We can check whether the obtained solution is correct or wrong. All we need to do is substituting the value of ‘w’ in the given problem.
\[4(4 - (1)) = 3(2(1) + 2)\]
\[
4(4 - 1) = 3(2 + 2) \\
4(3) = 3(4) \\
\Rightarrow 12 = 12 \;
\]
Complete step by step solution:
Given, \[4(4 - w) = 3(2w + 2)\] .
Expanding the brackets we have,
\[16 - 4w = 6w + 6\]
We transpose \[16\] which is present in the left hand side of the equation to the right hand side of the equation by subtracting \[16\] on the right hand side of the equation.
\[ - 4w = 6w + 6 - 16\]
We transpose \[6w\] to the right hand side of the equation by subtracting \[6w\] on the right hand side of the equation.
\[ - 6w - 4w = 6 - 16\]
\[ - 10w = - 10\]
Divide the whole equation by \[ - 10\] .
\[w = \dfrac{{ - 10}}{{ - 10}}\]
\[ \Rightarrow w = 1\] is the required answer.
So, the correct answer is “w = 1”.
Note: We can check whether the obtained solution is correct or wrong. All we need to do is substituting the value of ‘w’ in the given problem.
\[4(4 - (1)) = 3(2(1) + 2)\]
\[
4(4 - 1) = 3(2 + 2) \\
4(3) = 3(4) \\
\Rightarrow 12 = 12 \;
\]
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Trending doubts
How many sides does a circle have a 10 sides b 20 sides class 8 maths CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

What does the color green in the national flag of India class 8 social science CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Full form of STD, ISD and PCO

One cusec is equal to how many liters class 8 maths CBSE

