
How do you simplify $ 15+(12+8a) $?
Answer
546k+ views
Hint: In the question, we are given a mathematical equation that is a combination of both numerical values and alphabets; such types of mathematical equations are called algebraic expressions. The representation of numbers by alphabets in a formula or equation involving mathematical operations is known as algebra. Here ‘8a’ represents the multiplication of ‘8’ and ‘a’
Complete step-by-step answer:
We separate the ‘a’ term and constant numbers.
We have to simplify \[15 + (12 + 8a)\] .
Now we can regroup this as
\[ \Rightarrow (15 + 12) + 8a\] .
We have 15 and 12, we need to add this. We get:
\[ \Rightarrow (15 + 12) + 8a\]
\[ \Rightarrow 27 + 8a\]
Therefore the simplified form is 27+8a.
So, the correct answer is “27+8a”.
Note: If they give any mathematical equation, to simplify that we always separate the constants and the variable containing the terms. Variable means the unknown value or value that needs to be found. If we have two terms containing the same variable we take the common and apply the algebraic operations. For example if we have “10a+15a” all we need to do is take the variable ‘a’ common and add the number, we get the required result. That is “a(10+15)” is equal to “25a”.
Complete step-by-step answer:
We separate the ‘a’ term and constant numbers.
We have to simplify \[15 + (12 + 8a)\] .
Now we can regroup this as
\[ \Rightarrow (15 + 12) + 8a\] .
We have 15 and 12, we need to add this. We get:
\[ \Rightarrow (15 + 12) + 8a\]
\[ \Rightarrow 27 + 8a\]
Therefore the simplified form is 27+8a.
So, the correct answer is “27+8a”.
Note: If they give any mathematical equation, to simplify that we always separate the constants and the variable containing the terms. Variable means the unknown value or value that needs to be found. If we have two terms containing the same variable we take the common and apply the algebraic operations. For example if we have “10a+15a” all we need to do is take the variable ‘a’ common and add the number, we get the required result. That is “a(10+15)” is equal to “25a”.
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