How do you factor \[6{x^2} - 5x - 25\] ?
Answer
585.3k+ views
Hint: Here in this question they have given the expression and it is an algebraic expression where it contains variables and constant terms. We have to find the factor \[6{x^2} - 5x - 25\] , so divide it by using variables and constants and hence find the solution.
We are going to use splitting the middle term method to factorise the given quadratic polynomial.
Complete step-by-step answer:
The equation \[6{x^2} - 5x - 25\] is a quadratic equation and we get two factors on factorization. This equation is an algebraic equation which contains both constant term and variable term. To find the factor for the equation \[6{x^2} - 5x - 25\] we have a rule and it is a sum-product rule. To find the factors let we equate it to zero \[6{x^2} - 5x - 25 = 0\]
{Generally, the sum-product rule of the equation is
Consider the equation in general \[a{x^2} + bx + c = 0\] where the product of a and c is written as sum of b. The numbers should satisfy the b by applying the sum rule. Here the sign convention plays an important role.}
Now consider the equation \[6{x^2} - 5x - 25 = 0\] , here a= 6 b=-5 and c=-25
The product of ac is -150
The factors of -150 is 10 and -15 and the factors of -150 is -10 and 15
Now we will check which factors on the sum rule will satisfy the b
If we apply the sum rule to 10 and -15 the answer is -5
If we apply the sum rule to -10 and 15 the answer is 5
So we will consider 10 and -15 as factors of -150
Therefore the equation can be written as
\[6{x^2} - 5x - 25 = 0\]
\[ \Rightarrow 6{x^2} + 10x - 15x - 25 = 0\]
Rearrange the terms in the equation
\[ \Rightarrow 6{x^2} + 10x - 15x - 25 = 0\]
Let we take 2x as common in \[6{x^2} + 10x\] and -5 as common in \[ - 15x - 25\] and the equation is written as
\[ \Rightarrow 2x(3x + 5) - 5(3x + 5) = 0\]
Take (3x+5) as common in the above equation we have
\[(3x + 5)(2x - 5) = 0\]
Therefore the factors of \[6{x^2} - 5x - 25 = 0\] is \[(3x + 5)(2x - 5) = 0\]
So, the correct answer is “ \[(3x + 5)(2x - 5) = 0\] ”.
Note: The sum product rule is used to find the factors and will obtain the solution for the question. In general the sum product is given as the equation in general \[a{x^2} + bx + c = 0\] where the product of a and c is written as sum of b. The numbers should satisfy the b by applying the sum rule. Here the sign convention plays an important role. The sign conventions should be known to satisfy the equation.
We are going to use splitting the middle term method to factorise the given quadratic polynomial.
Complete step-by-step answer:
The equation \[6{x^2} - 5x - 25\] is a quadratic equation and we get two factors on factorization. This equation is an algebraic equation which contains both constant term and variable term. To find the factor for the equation \[6{x^2} - 5x - 25\] we have a rule and it is a sum-product rule. To find the factors let we equate it to zero \[6{x^2} - 5x - 25 = 0\]
{Generally, the sum-product rule of the equation is
Consider the equation in general \[a{x^2} + bx + c = 0\] where the product of a and c is written as sum of b. The numbers should satisfy the b by applying the sum rule. Here the sign convention plays an important role.}
Now consider the equation \[6{x^2} - 5x - 25 = 0\] , here a= 6 b=-5 and c=-25
The product of ac is -150
The factors of -150 is 10 and -15 and the factors of -150 is -10 and 15
Now we will check which factors on the sum rule will satisfy the b
If we apply the sum rule to 10 and -15 the answer is -5
If we apply the sum rule to -10 and 15 the answer is 5
So we will consider 10 and -15 as factors of -150
Therefore the equation can be written as
\[6{x^2} - 5x - 25 = 0\]
\[ \Rightarrow 6{x^2} + 10x - 15x - 25 = 0\]
Rearrange the terms in the equation
\[ \Rightarrow 6{x^2} + 10x - 15x - 25 = 0\]
Let we take 2x as common in \[6{x^2} + 10x\] and -5 as common in \[ - 15x - 25\] and the equation is written as
\[ \Rightarrow 2x(3x + 5) - 5(3x + 5) = 0\]
Take (3x+5) as common in the above equation we have
\[(3x + 5)(2x - 5) = 0\]
Therefore the factors of \[6{x^2} - 5x - 25 = 0\] is \[(3x + 5)(2x - 5) = 0\]
So, the correct answer is “ \[(3x + 5)(2x - 5) = 0\] ”.
Note: The sum product rule is used to find the factors and will obtain the solution for the question. In general the sum product is given as the equation in general \[a{x^2} + bx + c = 0\] where the product of a and c is written as sum of b. The numbers should satisfy the b by applying the sum rule. Here the sign convention plays an important role. The sign conventions should be known to satisfy the equation.
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