
How do you differentiate \[y={{\log }_{5}}x\]?
Answer
554.1k+ views
Hint: Simplify the logarithmic function by using the base change formula given as: - \[{{\log }_{a}}b=\dfrac{{{\log }_{c}}b}{{{\log }_{c}}a}\]. Convert the base of the logarithm into ‘e’, that means into natural logarithm (ln). Now, differentiate both the sides of the function with respect to the variable x and use the formula: - \[\dfrac{d\left[ \ln x \right]}{dx}=\dfrac{1}{x}\] to simplify and get the answer.
Complete step by step answer:
Here, we have been provided with the logarithmic function \[y={{\log }_{5}}x\] and we are asked to differentiate it. That means we have to find the value of \[\dfrac{dy}{dx}\].
Now, we know that we have a direct derivative formula for the natural logarithmic function given as \[\dfrac{d\left[ \ln x \right]}{dx}=\dfrac{1}{x}\]. Natural log means the base of the logarithm must be ‘e’. Here, \[e\simeq 2.71\]. We do not have a direct formula for the logarithmic functions having bases other than e, so to differentiate such functions first we have to convert them into natural log. This is done using the base change formula in logarithms.
In the above question we have \[y={{\log }_{5}}x\], here we have the base of the logarithm equal to 5 which is a constant other than e. Applying the base change rule given as: - \[{{\log }_{a}}b=\dfrac{{{\log }_{c}}b}{{{\log }_{c}}a}\], we have,
\[\Rightarrow {{\log }_{5}}x=\dfrac{{{\log }_{e}}x}{{{\log }_{e}}5}\]
This can be written as: -
\[\Rightarrow y=\dfrac{\log x}{\log 5}\]
Now, differentiating both the sides with respect to the variable x, we get,
\[\Rightarrow \dfrac{dy}{dx}=\dfrac{d\left( \dfrac{\ln x}{\ln 5} \right)}{dx}\]
Since, \[\ln 5\] is a constant, so it can be taken out of the derivative, so we get,
\[\Rightarrow \dfrac{dy}{dx}=\dfrac{1}{\ln 5}\dfrac{d\ln x}{dx}\]
Using the formula: - \[\dfrac{d\left[ \ln x \right]}{dx}=\dfrac{1}{x}\], we get,
\[\begin{align}
& \Rightarrow \dfrac{dy}{dx}=\dfrac{1}{\ln 5}\times \dfrac{1}{x} \\
& \Rightarrow \dfrac{dy}{dx}=\dfrac{1}{x\ln 5} \\
\end{align}\]
Hence, the derivative of the given function is \[\dfrac{1}{x\ln 5}\].
Note: One must remember the base change formula of the logarithm to solve the above question. You must not convert the given logarithm into common log, i.e., log to the base 10, because it will be of no use here. We do not have a derivative formula for common log. Remember all the basic formulas of logarithm like: - \[\log m+\log n=\log \left( mn \right)\], \[\log m-\log n=\log \left( \dfrac{m}{n} \right)\], \[\log {{a}^{m}}=m\log a\] etc. as they are frequently used. You can further simplify the answer by using the conversion: - \[\dfrac{1}{\ln a}={{\log }_{a}}e\], where a= 5.
Complete step by step answer:
Here, we have been provided with the logarithmic function \[y={{\log }_{5}}x\] and we are asked to differentiate it. That means we have to find the value of \[\dfrac{dy}{dx}\].
Now, we know that we have a direct derivative formula for the natural logarithmic function given as \[\dfrac{d\left[ \ln x \right]}{dx}=\dfrac{1}{x}\]. Natural log means the base of the logarithm must be ‘e’. Here, \[e\simeq 2.71\]. We do not have a direct formula for the logarithmic functions having bases other than e, so to differentiate such functions first we have to convert them into natural log. This is done using the base change formula in logarithms.
In the above question we have \[y={{\log }_{5}}x\], here we have the base of the logarithm equal to 5 which is a constant other than e. Applying the base change rule given as: - \[{{\log }_{a}}b=\dfrac{{{\log }_{c}}b}{{{\log }_{c}}a}\], we have,
\[\Rightarrow {{\log }_{5}}x=\dfrac{{{\log }_{e}}x}{{{\log }_{e}}5}\]
This can be written as: -
\[\Rightarrow y=\dfrac{\log x}{\log 5}\]
Now, differentiating both the sides with respect to the variable x, we get,
\[\Rightarrow \dfrac{dy}{dx}=\dfrac{d\left( \dfrac{\ln x}{\ln 5} \right)}{dx}\]
Since, \[\ln 5\] is a constant, so it can be taken out of the derivative, so we get,
\[\Rightarrow \dfrac{dy}{dx}=\dfrac{1}{\ln 5}\dfrac{d\ln x}{dx}\]
Using the formula: - \[\dfrac{d\left[ \ln x \right]}{dx}=\dfrac{1}{x}\], we get,
\[\begin{align}
& \Rightarrow \dfrac{dy}{dx}=\dfrac{1}{\ln 5}\times \dfrac{1}{x} \\
& \Rightarrow \dfrac{dy}{dx}=\dfrac{1}{x\ln 5} \\
\end{align}\]
Hence, the derivative of the given function is \[\dfrac{1}{x\ln 5}\].
Note: One must remember the base change formula of the logarithm to solve the above question. You must not convert the given logarithm into common log, i.e., log to the base 10, because it will be of no use here. We do not have a derivative formula for common log. Remember all the basic formulas of logarithm like: - \[\log m+\log n=\log \left( mn \right)\], \[\log m-\log n=\log \left( \dfrac{m}{n} \right)\], \[\log {{a}^{m}}=m\log a\] etc. as they are frequently used. You can further simplify the answer by using the conversion: - \[\dfrac{1}{\ln a}={{\log }_{a}}e\], where a= 5.
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