
Hira and Sarita are friends. What is the probability that both will have –
I.Different birthdays?
II.The same birthday?
Answer
503.1k+ views
Hint: The term probability defines the term probable, the event which is likely to happen. Here we will use the definition of the probability which can be defined as the ratio of the favorable outcomes upon the total possible outcomes.
Complete step-by-step answer:
I.Here any non-leap year has total $ 365 $ days, therefore the total possible outcomes here will be $ n = 365 $
If both Sarita and Hamida were born on different days.
Let us assume that “A” is the event when both Sarita and Hamida were born on different day.
$ n(A) = 364 $
Now, the required probability can be given by –
$ P(A) = \dfrac{{n(A)}}{n} $
Place the values in the above expression –
$ P(A) = \dfrac{{364}}{{365}} $ ….. (A)
II.If both Sarita and Hamida were born on the same day
Let us assume that “B” be the event when both Sarita and Hamida were born on the same day.
$ n(B) = 1 $
Now, the required probability can be given by –
$ P(B) = \dfrac{{n(B)}}{n} $
Place the values in the above expression –
$ P(B) = \dfrac{1}{{365}} $ ….. (B)
Hence, the equations (A) and (B) are the required solution.
Note: Always remember that the probability of any event lies between zero and one. If the probability is expressed in the form of fraction, then the denominator is always bigger than the numerator. The probability of the sure event is always one and impossible event is always zero.
Complete step-by-step answer:
I.Here any non-leap year has total $ 365 $ days, therefore the total possible outcomes here will be $ n = 365 $
If both Sarita and Hamida were born on different days.
Let us assume that “A” is the event when both Sarita and Hamida were born on different day.
$ n(A) = 364 $
Now, the required probability can be given by –
$ P(A) = \dfrac{{n(A)}}{n} $
Place the values in the above expression –
$ P(A) = \dfrac{{364}}{{365}} $ ….. (A)
II.If both Sarita and Hamida were born on the same day
Let us assume that “B” be the event when both Sarita and Hamida were born on the same day.
$ n(B) = 1 $
Now, the required probability can be given by –
$ P(B) = \dfrac{{n(B)}}{n} $
Place the values in the above expression –
$ P(B) = \dfrac{1}{{365}} $ ….. (B)
Hence, the equations (A) and (B) are the required solution.
Note: Always remember that the probability of any event lies between zero and one. If the probability is expressed in the form of fraction, then the denominator is always bigger than the numerator. The probability of the sure event is always one and impossible event is always zero.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

