How do you graph \[x+5y=10\] using intercepts?
Answer
613.8k+ views
Hint: In order to graph the given equation, we have to first find the intercepts made by the line of the given equation with both the axis. To find the x intercept, put y=0 and similarly to find y intercept put x=0. With this we will get two sets of coordinates. To get the graph of the equation, draw a line passing through the points.
Complete step by step answer:
In the given question, the equation which we have to graph is \[3x+5y=10\] . Let us first see what is slope and intercept. Slope is defined as the gradient of the line. In simple terms we can say the tangent of the angle made by the line with x-axis. It is just the change of over the change of . On the other hand, the intercept is the point where the line crosses the - axis. The distance from that intersection point to the origin is the value of intercept.
Now the given equation is \[x+5y=10\] . let us find the x and y intercepts made by the line.
To find y intercept, put x=0
\[x+5y=10\] when \[x=0\]
We get,
\[\begin{align}
& x=0 \\
& 5y=10 \\
& y=2 \\
\end{align}\]
\[(0,2)\]
To find x intercept, put y=0
\[x+5y=10\] when \[y=0\]
We get,
\[\begin{align}
& x=10 \\
& (10,0) \\
\end{align}\]
Thus, the coordinates from which line passes is \[(0,2)\] and \[(10,0)\] . Draw a line passing through these two points.
Hence the above graph is for the given equation.
Note: While plotting the graph mark the coordinates carefully. The intercept formed by the line with x axis is 10 and the intercept formed by the line with y axis is 2. Write the equation just above the line drawn. Mark both the axes on the graph.
Complete step by step answer:
In the given question, the equation which we have to graph is \[3x+5y=10\] . Let us first see what is slope and intercept. Slope is defined as the gradient of the line. In simple terms we can say the tangent of the angle made by the line with x-axis. It is just the change of over the change of . On the other hand, the intercept is the point where the line crosses the - axis. The distance from that intersection point to the origin is the value of intercept.
Now the given equation is \[x+5y=10\] . let us find the x and y intercepts made by the line.
To find y intercept, put x=0
\[x+5y=10\] when \[x=0\]
We get,
\[\begin{align}
& x=0 \\
& 5y=10 \\
& y=2 \\
\end{align}\]
\[(0,2)\]
To find x intercept, put y=0
\[x+5y=10\] when \[y=0\]
We get,
\[\begin{align}
& x=10 \\
& (10,0) \\
\end{align}\]
Thus, the coordinates from which line passes is \[(0,2)\] and \[(10,0)\] . Draw a line passing through these two points.
Hence the above graph is for the given equation.
Note: While plotting the graph mark the coordinates carefully. The intercept formed by the line with x axis is 10 and the intercept formed by the line with y axis is 2. Write the equation just above the line drawn. Mark both the axes on the graph.
Recently Updated Pages
Difference Between Prokaryotic Cells and Eukaryotic Cells

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

