
How do you graph \[f\left( x \right) = {\left( {x + 2} \right)^2}?\]
Answer
552k+ views
Hint: The given question describes the operation of addition/ subtraction/ multiplication/ division. Also, this problem involves the operation of substituting the \[x\] values in the given equation to find \[y\] values. Also, \[y\] is the fraction of \[x\]. By using the values of \[x\] and \[y\] we can easily draw the graph. To make easy calculations we can simplify the given equation by using algebraic formulas.
Complete step by step solution:
The given question is shown below,
\[y = f\left( x \right) = {\left( {x + 2} \right)^2} \to \left( 1 \right)\]
We know that,
\[{\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab\]
By using the above-mentioned algebraic formula we can simplify the equation \[\left( 1 \right)\] as follows,
\[\left( 1 \right) \to y = {\left( {x + 2} \right)^2}\]
\[
y = {x^2} + 2 \times 2 \times x + {2^2} \\
y = {x^2} + 4x + 4 \to \left( 2 \right) \\
\]
We would draw the graph for the above equation.
As a first step, we would assume \[x\] value as given below,
\[x = ... - 2, - 1,0,1,2,.....\]
By substituting the above-mentioned \[x\] values in the equation \[\left( 2 \right)\], we can find the \[y\] values.
Let’s substitute \[x = - 2\] in the equation \[\left( 2 \right)\], we get
\[\left( 2 \right) \to y = {x^2} + 4x + 4\]
\[
y = {\left( { - 2} \right)^2} + \left( {4 \times - 2} \right) + 4 \\
y = 4 - 8 + 4 \\
y = 0 \\
\]
Let’s substitute\[x = - 1\] in the equation \[\left( 2 \right)\], we get
\[\left( 2 \right) \to y = {x^2} + 4x + 4\]
\[
y = {\left( { - 1} \right)^2} + 4\left( { - 1} \right) + 4 \\
y = 1 - 4 + 4 \\
y = 1 \\
\]
Let’s substitute \[x = 0\] in the equation \[\left( 2 \right)\], we get
\[\left( 2 \right) \to y = {x^2} + 4x + 4\]
\[
y = {\left( 0 \right)^2} + 4\left( 0 \right) + 4 \\
y = 4 \\
\]
Let’s substitute \[x = 1\] in the equation \[\left( 2 \right)\], we get
\[\left( 2 \right) \to y = {x^2} + 4x + 4\]
\[
y = {\left( 1 \right)^2} + 4\left( 1 \right) + 4 \\
y = 9 \\
\]
Let’s substitute \[x = 2\] in the equation \[\left( 2 \right)\], we get
\[\left( 2 \right) \to y = {x^2} + 4x + 4\]
\[
y = {\left( 2 \right)^2} + \left( {4 \times 2} \right) + 2 \\
y = 4 + 8 + 2 \\
y = 14 \\
\]
Let’s make a tabular column by using the\[x\]and\[y\]values as given below,
By using these points we can easily draw the graph.
The above graph represents the equation \[y\left( x \right) = {\left( {x + 2} \right)^2}\]
Note: In this type of question we would assume \[x\] value, by using the \[x\] value we can find the value of \[y\]. The graph could be based on the equation. \[y\] is the function of \[x\]. So, \[y\] also can be written as \[f\left( x \right)\]. Note that \[y = {x^2}\] the form equation always makes a parabolic shape in the graph sheet. Remember the algebraic formula \[{\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab\].
Complete step by step solution:
The given question is shown below,
\[y = f\left( x \right) = {\left( {x + 2} \right)^2} \to \left( 1 \right)\]
We know that,
\[{\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab\]
By using the above-mentioned algebraic formula we can simplify the equation \[\left( 1 \right)\] as follows,
\[\left( 1 \right) \to y = {\left( {x + 2} \right)^2}\]
\[
y = {x^2} + 2 \times 2 \times x + {2^2} \\
y = {x^2} + 4x + 4 \to \left( 2 \right) \\
\]
We would draw the graph for the above equation.
As a first step, we would assume \[x\] value as given below,
\[x = ... - 2, - 1,0,1,2,.....\]
By substituting the above-mentioned \[x\] values in the equation \[\left( 2 \right)\], we can find the \[y\] values.
Let’s substitute \[x = - 2\] in the equation \[\left( 2 \right)\], we get
\[\left( 2 \right) \to y = {x^2} + 4x + 4\]
\[
y = {\left( { - 2} \right)^2} + \left( {4 \times - 2} \right) + 4 \\
y = 4 - 8 + 4 \\
y = 0 \\
\]
Let’s substitute\[x = - 1\] in the equation \[\left( 2 \right)\], we get
\[\left( 2 \right) \to y = {x^2} + 4x + 4\]
\[
y = {\left( { - 1} \right)^2} + 4\left( { - 1} \right) + 4 \\
y = 1 - 4 + 4 \\
y = 1 \\
\]
Let’s substitute \[x = 0\] in the equation \[\left( 2 \right)\], we get
\[\left( 2 \right) \to y = {x^2} + 4x + 4\]
\[
y = {\left( 0 \right)^2} + 4\left( 0 \right) + 4 \\
y = 4 \\
\]
Let’s substitute \[x = 1\] in the equation \[\left( 2 \right)\], we get
\[\left( 2 \right) \to y = {x^2} + 4x + 4\]
\[
y = {\left( 1 \right)^2} + 4\left( 1 \right) + 4 \\
y = 9 \\
\]
Let’s substitute \[x = 2\] in the equation \[\left( 2 \right)\], we get
\[\left( 2 \right) \to y = {x^2} + 4x + 4\]
\[
y = {\left( 2 \right)^2} + \left( {4 \times 2} \right) + 2 \\
y = 4 + 8 + 2 \\
y = 14 \\
\]
Let’s make a tabular column by using the\[x\]and\[y\]values as given below,
| \[x\] | \[ - 2\] | \[ - 1\] | \[0\] | \[1\] | \[2\] |
| \[y\] | \[0\] | \[1\] | \[4\] | \[9\] | \[14\] |
By using these points we can easily draw the graph.
The above graph represents the equation \[y\left( x \right) = {\left( {x + 2} \right)^2}\]
Note: In this type of question we would assume \[x\] value, by using the \[x\] value we can find the value of \[y\]. The graph could be based on the equation. \[y\] is the function of \[x\]. So, \[y\] also can be written as \[f\left( x \right)\]. Note that \[y = {x^2}\] the form equation always makes a parabolic shape in the graph sheet. Remember the algebraic formula \[{\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab\].
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

