What fraction of a clockwise revolution does the hour hand of a clock turn through when it goes from 12 to 9.
Answer
Verified
478.5k+ views
Hint: We know that the total number of segments in the clock is 12 and each segment is covered at the end of each hour. Use this concept to solve the problem.
Complete step-by-step answer:
Step 1 :
In a clock there are totally 12 segments.
We divide our clock into 12 segments
Each segment is covered at the end of every hour.
Step 2:
We are said that the hour hand of the clock goes from 12 to 9
This means that it has been 9 hours
So this tells us that 9 segments have been covered .
And the total number of segments is 12.
Hence the fraction is given as
$
\Rightarrow \dfrac{9}{{12}} \\
\Rightarrow \dfrac{3}{4} \\
$
Therefore the fraction covered by the clockwise movement of the hour hand from 12 to 9 is $\dfrac{3}{4}$.
Note: 1.Every fraction has a numerator that equals the number of parts we have and a denominator equaling the total number of parts in a whole.
2.Any fraction with a Denominator of 1 is equal to its Numerator
Complete step-by-step answer:
Step 1 :
In a clock there are totally 12 segments.
We divide our clock into 12 segments
Each segment is covered at the end of every hour.
Step 2:
We are said that the hour hand of the clock goes from 12 to 9
This means that it has been 9 hours
So this tells us that 9 segments have been covered .
And the total number of segments is 12.
Hence the fraction is given as
$
\Rightarrow \dfrac{9}{{12}} \\
\Rightarrow \dfrac{3}{4} \\
$
Therefore the fraction covered by the clockwise movement of the hour hand from 12 to 9 is $\dfrac{3}{4}$.
Note: 1.Every fraction has a numerator that equals the number of parts we have and a denominator equaling the total number of parts in a whole.
2.Any fraction with a Denominator of 1 is equal to its Numerator
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