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What is the formula of brown ppt?
(A) Cu2I2
(B) Cu2I2+I3
(C) CuI2
(D) CuSO4

Answer
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Hint: Copper is a transition metal with the ability to show variable oxidation states and also d-d transitions that are responsible for imparting colour to its compounds and precipitates. But all oxidation states of copper cannot show d-d transitions.

Complete answer:
The electronic configuration of copper in its +1 oxidation state is 3d10 and that of copper in its +2 oxidation state is 3d9 . Thus, copper in its +2 oxidation state has one vacant space in the d orbital for an electron but copper in its +1 oxidation state has no vacant spaces and a completely filled d-orbital.
Transition metals ions that have a fully filled d-orbital are incapable of showing d-d transitions that are mainly responsible for imparting colour to these ions. Each ion in its particular oxidation state shows a characteristic colour depending upon the wavelength of the d-d transitions that take place.
Salts formed by copper Cu2+ ions have a characteristic blue colour due to the presence of d-d transitions associated with the partially filled d-orbital. Hence, CuI2 and CuSO4 are blue coloured salts.
The copper ions in +1 oxidation state are mainly colorless or white due to the absence of d-d transitions. Therefore a copper salt alone cannot form a brown precipitate. But iodine gas in the presence of potassium iodide forms triiodide ions which are initially yellow but turn dark brown in colour upon standing.
 I2+KII3
These triiodide ions get adsorbed on the surface of colourless precipitate of copper resulting in a coloured precipitate
 (Cu2I2+I3) this combination is brown in colour.
Hence, the correct option is (b) and the brown precipitate is due to the formation of (Cu2I2+I3) .

Note:
Not all transition metal compounds and complexes are coloured solely due to the d-d transitions. Many complexes get their colour due to the presence of ligands that are conjugated in nature or due to charge transfer phenomenon.