
For MRI, a patient is slowly pushed in a time of 10s within the coils of the magnet where the magnetic field is B = 2.0T. If the patient’s trunk is 0.8m in circumference, the induced EMF around the patient’s trunk is:
A) 10.18$ \times $ 10-2 V
B) 9.66 $ \times $102V
C) 10.18$ \times $ 10-3 V
D) 1.5$ \times $10-2V
Answer
578.1k+ views
Hint:
The question is asking about the induced EMF and the concept of induced EMF is given by Faraday’s Law:
$E = - \dfrac{{d\phi }}{{dt}}$ (Where $\phi $ is the flux induced, E is the EMF, t is the time)
Minus sign in the above equation comes from the Lenz law.
Using the above two laws we will conclude the problem.
Complete step by step solution:
Faraday’s law states that: Any change in the magnetic environment of the coil of conductors will cause a voltage (EMF) to be induced in the coil.
$E = - \dfrac{{d\phi }}{{dt}}$
Generally the change in flux takes place or we can say that the rate of change of flux causes induced EMF.
Electric Flux: electric flux is the property of an electric field that may be thought of as the number of electric lines of force that intersect at a given point.
Let’s calculate the EMF induced:
We have: $E = - \dfrac{{d\phi }}{{dt}}$
We can write $\phi $ = BA ( B is the magnetic field and A is the area).
$\therefore E = - A\dfrac{{dB}}{{dt}}$................1
B = 2Tesla and the circumference of the trunk is given 0.8m.
To calculate the area we must have the radius of the trunk.
Circumference is:
$
\Rightarrow 2\pi r = 0.8 \\
\Rightarrow r = \dfrac{{0.8}}{{2\pi }} = 0.127m \\
$
Radius of the circumference is 0.127m
Now area of the trunk:
$ \Rightarrow \pi {r^2} = \pi {\left( {0.127} \right)^2}$
$ \Rightarrow \pi {r^2} = \pi {\left( {0.127} \right)^2} =. 0509{m^2}$
We substitute all the values in equation 1
$
\Rightarrow E = -. 0509 \times \dfrac{2}{{10}} \\
\Rightarrow E =. 1019 \times {10^{ - 1}} \\
$
$ \Rightarrow E = 10.19 \times {10^{ - 3}}$ (Multiply the numerator and denominator by 100)
Option 3 is correct.
Note:Lenz law which we have mentioned above states that the direction of the electric current which is induced in a conductor by a changing magnetic field is such that the magnetic field created by the induced current opposes the initial changing magnetic field.
The question is asking about the induced EMF and the concept of induced EMF is given by Faraday’s Law:
$E = - \dfrac{{d\phi }}{{dt}}$ (Where $\phi $ is the flux induced, E is the EMF, t is the time)
Minus sign in the above equation comes from the Lenz law.
Using the above two laws we will conclude the problem.
Complete step by step solution:
Faraday’s law states that: Any change in the magnetic environment of the coil of conductors will cause a voltage (EMF) to be induced in the coil.
$E = - \dfrac{{d\phi }}{{dt}}$
Generally the change in flux takes place or we can say that the rate of change of flux causes induced EMF.
Electric Flux: electric flux is the property of an electric field that may be thought of as the number of electric lines of force that intersect at a given point.
Let’s calculate the EMF induced:
We have: $E = - \dfrac{{d\phi }}{{dt}}$
We can write $\phi $ = BA ( B is the magnetic field and A is the area).
$\therefore E = - A\dfrac{{dB}}{{dt}}$................1
B = 2Tesla and the circumference of the trunk is given 0.8m.
To calculate the area we must have the radius of the trunk.
Circumference is:
$
\Rightarrow 2\pi r = 0.8 \\
\Rightarrow r = \dfrac{{0.8}}{{2\pi }} = 0.127m \\
$
Radius of the circumference is 0.127m
Now area of the trunk:
$ \Rightarrow \pi {r^2} = \pi {\left( {0.127} \right)^2}$
$ \Rightarrow \pi {r^2} = \pi {\left( {0.127} \right)^2} =. 0509{m^2}$
We substitute all the values in equation 1
$
\Rightarrow E = -. 0509 \times \dfrac{2}{{10}} \\
\Rightarrow E =. 1019 \times {10^{ - 1}} \\
$
$ \Rightarrow E = 10.19 \times {10^{ - 3}}$ (Multiply the numerator and denominator by 100)
Option 3 is correct.
Note:Lenz law which we have mentioned above states that the direction of the electric current which is induced in a conductor by a changing magnetic field is such that the magnetic field created by the induced current opposes the initial changing magnetic field.
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