
For \[\dfrac{N}{100}\]\[{{H}_{2}}S{{O}_{4}}\] , pH value is:
A. 2
B. 0.586
C. 0.856
D. None
Answer
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Hint: Here ‘N’ represents the normality of the solution. The normality is used for measuring the concentration of the solution. Normality is defined as the number of moles equivalent of the solute which is present in one litre of the solution. pH is the potential of hydrogen which determines the basicity or acidity of the substance.
Complete step-by-step answer:
So we know that the pH of the solution gives us the idea about the strength of the solution. The term pH is used to measure the acidity of the solution in the terms of the concentration of the hydrogen ions in the solution. pH is equal to the negative logarithm of the concentration of the hydrogen ions which have been released in the solution. The formula of pH is expressed as
\[pH=-\log [{{H}^{+}}]\]
So for finding the pH of the substance we need to know the concentration of hydronium ion present in the solution. Here they have given us the normality of sulphuric acid which is equal to 0.01 N as \[\dfrac{1}{100}\] is equal to 0.01. so we have 0.01 concentration of hydronium ions in the solution. We can write 0.01 as \[{{10}^{-2}}\].
Ao now substituting the values in the formula we get,
pH=\[-\log {{10}^{-2}}\]
on simplifying it we get
pH=2
So the pH of \[\dfrac{N}{100}\]\[{{H}_{2}}S{{O}_{4}}\] is 2.
So the correct answer is option (A).
Note:If pH is between 1 to 7 that means the solution is acidic. If the pH is equal to 7 that means the solution has been completely neutralised. If the pH is more than 7 then the solution is basic. The solution is neutral if the number of hydroxyl ions and hydronium ions are equal in solution.
Complete step-by-step answer:
So we know that the pH of the solution gives us the idea about the strength of the solution. The term pH is used to measure the acidity of the solution in the terms of the concentration of the hydrogen ions in the solution. pH is equal to the negative logarithm of the concentration of the hydrogen ions which have been released in the solution. The formula of pH is expressed as
\[pH=-\log [{{H}^{+}}]\]
So for finding the pH of the substance we need to know the concentration of hydronium ion present in the solution. Here they have given us the normality of sulphuric acid which is equal to 0.01 N as \[\dfrac{1}{100}\] is equal to 0.01. so we have 0.01 concentration of hydronium ions in the solution. We can write 0.01 as \[{{10}^{-2}}\].
Ao now substituting the values in the formula we get,
pH=\[-\log {{10}^{-2}}\]
on simplifying it we get
pH=2
So the pH of \[\dfrac{N}{100}\]\[{{H}_{2}}S{{O}_{4}}\] is 2.
So the correct answer is option (A).
Note:If pH is between 1 to 7 that means the solution is acidic. If the pH is equal to 7 that means the solution has been completely neutralised. If the pH is more than 7 then the solution is basic. The solution is neutral if the number of hydroxyl ions and hydronium ions are equal in solution.
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