Answer
405.3k+ views
Hint: We need to solve the two expressions and need to find the values for which the term x will be true in both the cases. And then comparing the two individual sets of values we need to just find the required solution.
Complete step-by-step answer:
The two sets A and B are given as below:
A = {x|x ϵ R, $ {x^2} - 3x - 4 = 0 $ }, where x belongs to any real number (R).
B = {x|x ϵ Z, $ {x^2} = x $ }, where x belongs to any integer (Z).
Now, let us solve the first equation using middle term factorization and find the values of x.
A = { x|x ϵ R, $ {x^2} - 3x - 4 = 0 $ }, where x belongs to any real number (R);
$ \Rightarrow {x^2} - 3x - 4 = 0 $
$ \Rightarrow {x^2} - 4x - x - 4 = 0 $
$ \Rightarrow x(x - 4) + 1(x - 4) = 0 $
$ \Rightarrow (x + 1)(x - 4) = 0 $
i.e. $ (x + 1) = 0 $ & $ (x - 4) = 0 $
So, $ x = - 1 $ or $ x = 4 $
Hence, for the given set A = {x|x ϵ R, $ {x^2} - 3x - 4 = 0 $ }
$ \Rightarrow $ A = { -1,4 }
Now, let us solve the second equation and find the values of x.
B = {x|x ϵ Z, $ {x^2} = x $ }, where x belongs to any integer (Z).
$ {x^2} = x $
There are only two values i.e., 0 and 1 for which $ {x^2} = x $ .
$ \Rightarrow $ B = {0,1}
I.Now, considering the above derived two sets we need to find A∩B & A∆B
A∩B means intersection of A and B i.e. the common values in set A and B.
Hence, A∩B = {-1,4}∩{0,1}
i.e. A∩B = ф ; where ф denotes an empty set.
II.And A∆B denotes symmetric difference i.e., the set of elements which are in either of the sets but they are not present in their intersections. In other words, the set of elements of both the sets excluding the common elements present in each set.
So, A∆B = {-1,4,0,1}
Hence, A∩B = ф ; where ф denotes empty set & A∆B = {-1,4,0,1,}.
So, the correct answer is “ A∆B = {-1,4,0,1,}.AND A∩B = ф ”.
Note: Kindly don’t get confuse in between A∩B & A∆B. The first one resembles the common terms only and the second term resembles the symmetric difference i.e., the set of elements which are in either of the sets but they are not present in their intersections. So, we need to be attentive while finding the answer from the derived sets.
Complete step-by-step answer:
The two sets A and B are given as below:
A = {x|x ϵ R, $ {x^2} - 3x - 4 = 0 $ }, where x belongs to any real number (R).
B = {x|x ϵ Z, $ {x^2} = x $ }, where x belongs to any integer (Z).
Now, let us solve the first equation using middle term factorization and find the values of x.
A = { x|x ϵ R, $ {x^2} - 3x - 4 = 0 $ }, where x belongs to any real number (R);
$ \Rightarrow {x^2} - 3x - 4 = 0 $
$ \Rightarrow {x^2} - 4x - x - 4 = 0 $
$ \Rightarrow x(x - 4) + 1(x - 4) = 0 $
$ \Rightarrow (x + 1)(x - 4) = 0 $
i.e. $ (x + 1) = 0 $ & $ (x - 4) = 0 $
So, $ x = - 1 $ or $ x = 4 $
Hence, for the given set A = {x|x ϵ R, $ {x^2} - 3x - 4 = 0 $ }
$ \Rightarrow $ A = { -1,4 }
Now, let us solve the second equation and find the values of x.
B = {x|x ϵ Z, $ {x^2} = x $ }, where x belongs to any integer (Z).
$ {x^2} = x $
There are only two values i.e., 0 and 1 for which $ {x^2} = x $ .
$ \Rightarrow $ B = {0,1}
I.Now, considering the above derived two sets we need to find A∩B & A∆B
A∩B means intersection of A and B i.e. the common values in set A and B.
Hence, A∩B = {-1,4}∩{0,1}
i.e. A∩B = ф ; where ф denotes an empty set.
II.And A∆B denotes symmetric difference i.e., the set of elements which are in either of the sets but they are not present in their intersections. In other words, the set of elements of both the sets excluding the common elements present in each set.
So, A∆B = {-1,4,0,1}
Hence, A∩B = ф ; where ф denotes empty set & A∆B = {-1,4,0,1,}.
So, the correct answer is “ A∆B = {-1,4,0,1,}.AND A∩B = ф ”.
Note: Kindly don’t get confuse in between A∩B & A∆B. The first one resembles the common terms only and the second term resembles the symmetric difference i.e., the set of elements which are in either of the sets but they are not present in their intersections. So, we need to be attentive while finding the answer from the derived sets.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)