
For a common emitter circuit if \[{{{I}_{C}}}/{{{I}_{E}}}\;=0.98\] then current gain for common emitter circuit will be
(A) \[4.9\]
(B) \[98\]
(C) \[49\]
(D) \[9.8\]
Answer
585.9k+ views
Hint: In a transistor, emitter current is equal to the sum of collector current and base current; and the current gain for the common-emitter circuit is ratio of collector current to base current.
Formula used:
The current gain \[\beta \] for a common-emitter circuit is given by:
\[\beta =\dfrac{{{I}_{C}}}{{{I}_{B}}}\]
Here \[{{I}_{C}}\]implies the collector current and \[{{I}_{B}}\] implies the base-current.
Complete step by step answer:
The ratio of collector current to emitter current, \[\dfrac{{{I}_{C}}}{{{I}_{E}}}=0.98\]
So, \[{{I}_{C}}=0.98{{I}_{E}}\]
In a transistor, emitter current is equal to the sum of collector current and base current, that is,
\[{{I}_{E}}={{I}_{B}}+{{I}_{C}}\] …..(i)
Where \[{{I}_{E}}\] is the emitter current, \[{{I}_{B}}\] is the base current and \[{{I}_{C}}\] is the collector current.
Substitute the value of \[{{I}_{C}}\] in equation (i):
\[{{I}_{E}}={{I}_{B}}+0.98{{I}_{E}}\]…..(ii)
Rearrange equation (ii) to get the value of base current \[{{I}_{B}}\] in terms of \[{{I}_{E}}\] :
\[\begin{align}
& {{I}_{E}}={{I}_{B}}+0.98{{I}_{E}} \\
& {{I}_{B}}={{I}_{E}}-0.98{{I}_{E}} \\
& {{I}_{B}}=0.02{{I}_{E}} \\
\end{align}\]
Now, current gain, \[\beta =\dfrac{{{I}_{C}}}{{{I}_{B}}}\]
Substitute \[{{I}_{C}}=0.98{{I}_{E}}\] and \[{{I}_{B}}=0.02{{I}_{E}}\] in the current gain formula:
\[\beta =\dfrac{0.98{{I}_{E}}}{0.02{{I}_{E}}}=49\].
Therefore, current gain for the common emitter circuit is \[49\].
Hence, option C is the correct answer.
Additional information:
In a common emitter circuit, the change in collector current due to change in base current, causes a change in collector-emitter voltage and the voltage drop across the load resistor, because collector supply voltage is fixed.
In a transistor connected in CE mode input current is \[{{I}_{B}}\] and output current is \[{{I}_{C}}\].
The d.c. current gain depends on the collector current and temperature.
The ratio of collector current to emitter current is called transistor alpha \[\alpha \]. Usually in god transistors \[\alpha \] ranges from \[0.98\] to \[0.988\].
Note:Always remember that current gain is the ratio of output current to the input current so it has no units.Most of the students get confused in it.
Formula used:
The current gain \[\beta \] for a common-emitter circuit is given by:
\[\beta =\dfrac{{{I}_{C}}}{{{I}_{B}}}\]
Here \[{{I}_{C}}\]implies the collector current and \[{{I}_{B}}\] implies the base-current.
Complete step by step answer:
The ratio of collector current to emitter current, \[\dfrac{{{I}_{C}}}{{{I}_{E}}}=0.98\]
So, \[{{I}_{C}}=0.98{{I}_{E}}\]
In a transistor, emitter current is equal to the sum of collector current and base current, that is,
\[{{I}_{E}}={{I}_{B}}+{{I}_{C}}\] …..(i)
Where \[{{I}_{E}}\] is the emitter current, \[{{I}_{B}}\] is the base current and \[{{I}_{C}}\] is the collector current.
Substitute the value of \[{{I}_{C}}\] in equation (i):
\[{{I}_{E}}={{I}_{B}}+0.98{{I}_{E}}\]…..(ii)
Rearrange equation (ii) to get the value of base current \[{{I}_{B}}\] in terms of \[{{I}_{E}}\] :
\[\begin{align}
& {{I}_{E}}={{I}_{B}}+0.98{{I}_{E}} \\
& {{I}_{B}}={{I}_{E}}-0.98{{I}_{E}} \\
& {{I}_{B}}=0.02{{I}_{E}} \\
\end{align}\]
Now, current gain, \[\beta =\dfrac{{{I}_{C}}}{{{I}_{B}}}\]
Substitute \[{{I}_{C}}=0.98{{I}_{E}}\] and \[{{I}_{B}}=0.02{{I}_{E}}\] in the current gain formula:
\[\beta =\dfrac{0.98{{I}_{E}}}{0.02{{I}_{E}}}=49\].
Therefore, current gain for the common emitter circuit is \[49\].
Hence, option C is the correct answer.
Additional information:
In a common emitter circuit, the change in collector current due to change in base current, causes a change in collector-emitter voltage and the voltage drop across the load resistor, because collector supply voltage is fixed.
In a transistor connected in CE mode input current is \[{{I}_{B}}\] and output current is \[{{I}_{C}}\].
The d.c. current gain depends on the collector current and temperature.
The ratio of collector current to emitter current is called transistor alpha \[\alpha \]. Usually in god transistors \[\alpha \] ranges from \[0.98\] to \[0.988\].
Note:Always remember that current gain is the ratio of output current to the input current so it has no units.Most of the students get confused in it.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

