
When fluorine is reacted with cold dilute alkali, which of the following is obtained as a product ?
(A) ${O_{_2}}$
(B) ${O_2}{F_2}$
(C) $O{F_2}$
(D) ${H_2}$
Answer
484.2k+ views
Hint: $O{F_2}$ ( oxygen difluoride) is prepared by the reaction between fluorine and dilute aqueous solution of sodium hydroxide. It’s an oxygen halide.$NaOH$ , sodium hydroxide also called caustic soda, when it's hot and concentrated, reacts violently but when cold and dilute does not react violently.
Complete step by step answer:
The reaction between and cold and dilute $NaOH$ and Fluorine gas is given as ,
$4{F_2} + 6NaOH \to O{F_2} + 6NaF + 3{H_2}O + {O_2}$
$NaF$ ( sodium fluoride ) is formed as the byproduct .
Fluorine is available in two oxidation states , 0 and -1 i.e. ${F_2}$ and ${F^ - }$Here we are taking ${F_2}$ as the reactant.
This reaction is a disproportionation reaction, where fluorine is reduced to sodium fluoride as well as it is oxidized to oxygen difluoride.Such a reaction in which there is simultaneous oxidation and reduction of the same reactant is called a disproportionation reaction, a type of redox reaction.Now, when fluorine gas reacts with hot and concentrated sodium hydroxide ,
$2{F_2} + 4NaOH \to 4NaF + 2{H_2}O + {O_2}$
Oxygen is released without the formation of $O{F_2}$ gas .Also, ${O_2}{F_2}$ ( dioxygen difluoride) is formed when fluorine gas reacts with oxygen gas.
${O_2} + {F_2} \to {O_2}{F_2}$
Hydrogen gas is prepared in the laboratory by the action of dilute acid like hydrochloric acid or sulphuric acid on zinc metal.
$Zn + 2HCl \to ZnC{l_2} + {H_2} \uparrow $
$Zn + {H_2}S{O_4} \to ZnS{O_4} + {H_2} \uparrow $
So, the correct answer is Option C .
Note: Oxygen is released during the decomposition of water
${H_2}O \to {H_2} + {O_2}$
And also during the reaction between fluorine gas and hot and concentrated sodium hydroxide.Oxygen difluoride, $O{F_2}$ is used as an oxidizer but is a hazardous, colorless gas.It’s a strong oxidizing agent.
Complete step by step answer:
The reaction between and cold and dilute $NaOH$ and Fluorine gas is given as ,
$4{F_2} + 6NaOH \to O{F_2} + 6NaF + 3{H_2}O + {O_2}$
$NaF$ ( sodium fluoride ) is formed as the byproduct .
Fluorine is available in two oxidation states , 0 and -1 i.e. ${F_2}$ and ${F^ - }$Here we are taking ${F_2}$ as the reactant.
This reaction is a disproportionation reaction, where fluorine is reduced to sodium fluoride as well as it is oxidized to oxygen difluoride.Such a reaction in which there is simultaneous oxidation and reduction of the same reactant is called a disproportionation reaction, a type of redox reaction.Now, when fluorine gas reacts with hot and concentrated sodium hydroxide ,
$2{F_2} + 4NaOH \to 4NaF + 2{H_2}O + {O_2}$
Oxygen is released without the formation of $O{F_2}$ gas .Also, ${O_2}{F_2}$ ( dioxygen difluoride) is formed when fluorine gas reacts with oxygen gas.
${O_2} + {F_2} \to {O_2}{F_2}$
Hydrogen gas is prepared in the laboratory by the action of dilute acid like hydrochloric acid or sulphuric acid on zinc metal.
$Zn + 2HCl \to ZnC{l_2} + {H_2} \uparrow $
$Zn + {H_2}S{O_4} \to ZnS{O_4} + {H_2} \uparrow $
So, the correct answer is Option C .
Note: Oxygen is released during the decomposition of water
${H_2}O \to {H_2} + {O_2}$
And also during the reaction between fluorine gas and hot and concentrated sodium hydroxide.Oxygen difluoride, $O{F_2}$ is used as an oxidizer but is a hazardous, colorless gas.It’s a strong oxidizing agent.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Basicity of sulphurous acid and sulphuric acid are

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Trending doubts
Which one of the following is a true fish A Jellyfish class 12 biology CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

a Tabulate the differences in the characteristics of class 12 chemistry CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Why is the cell called the structural and functional class 12 biology CBSE

What are the major means of transport Explain each class 12 social science CBSE
