Answer
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Hint:. Before we solve this given question, we need to understand the term known as flocculation. Flocculation is the process in which the colloids come out of the suspension in the form of flakes either spontaneously or due to addition of any emulsifying agent.
Complete step by step answer:
Let us see some basic terms before solving the illustration;
- Flocculation-
It is the process in which the fine particles are caused to clump into a floc. In this process, gentle mixing takes place and this speeds up the rate of collision of particles. The destabilised particles are then aggregated into larger precipitates.
The process is affected by various factors including mixing time, intensity and speed.
- Flocculation value-
This is the minimum amount of an electrolyte required to coagulate a solution and is expressed in millimole per litre. According to the Hardy-Schultz rule, it depends on the valency or charge of the active ion. So, the correct answer is “Option A”.
Note: Looking towards the other options;
- Gram per litre is the unit of strength.
- Mole per litre and also mole per millilitre are the units of molarity.
- Thus, they could never have been the answer to our illustration.
Complete step by step answer:
Let us see some basic terms before solving the illustration;
- Flocculation-
It is the process in which the fine particles are caused to clump into a floc. In this process, gentle mixing takes place and this speeds up the rate of collision of particles. The destabilised particles are then aggregated into larger precipitates.
The process is affected by various factors including mixing time, intensity and speed.
- Flocculation value-
This is the minimum amount of an electrolyte required to coagulate a solution and is expressed in millimole per litre. According to the Hardy-Schultz rule, it depends on the valency or charge of the active ion. So, the correct answer is “Option A”.
Note: Looking towards the other options;
- Gram per litre is the unit of strength.
- Mole per litre and also mole per millilitre are the units of molarity.
- Thus, they could never have been the answer to our illustration.
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