# How can I find valence electrons of transition metals?

- So, transition metals are those whose last electrons enters in the d-subshell, therefore, the number of valence electrons will be: $n{{s}^{1-2}}(n-1){{d}^{1-10}}$. For example, the valence electron in iron will be 8 because the configuration of iron is $[Ar]3{{d}^{6}}4{{s}^{2}}$ so, the 6 electrons of d-subshell and 2 electrons of s-subshell is taken.