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Find three consecutive even numbers whose sum is 246.

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Hint: First of all we will have to know about the even number. Any integer that can be divided exactly by 2 is known as an even number. In the above question we will have to consider the consecutive even numbers, the numbers which follow each other in order , without gap , from smallest to largest. Also the even consecutive numbers always differ by 2.

Complete step-by-step answer:
Now, let us consider that we have the three consecutive even numbers a, (a+2) and (a+4).
$\begin{align}
  & \Rightarrow a+(a+2)+(a+4)=246 \\
 & \Rightarrow 3a=246-6 \\
 & \Rightarrow a=\dfrac{240}{3}=80 \\
\end{align}$
Hence, we have the three consecutive even numbers as 80, 82 and 84.

Note: Just remember all the properties of even as well as odd numbers that must help you a lot in the above type of question.
Also remember that any integer whose last digit is 0, 2, 4, 6, 8 are all even numbers.
Zero is the first non- negative even number. Two is the first positive even number.
One the properties of even numbers are that if we have two even numbers then their addition, subtraction as well as multiplication gives the result an even number.
Also remember that the even number can be represented in the form of 2N where N is any integer.