
Find the value of x + y if \[\left[ \begin{matrix}
x-y & z \\
2x-y & w \\
\end{matrix} \right]=\left[ \begin{matrix}
-1 & 4 \\
0 & 5 \\
\end{matrix} \right].\]
Answer
591.3k+ views
Hint: We are given two matrices \[\left[ \begin{matrix}
x-y & z \\
2x-y & w \\
\end{matrix} \right]\And \left[ \begin{matrix}
-1 & 4 \\
0 & 5 \\
\end{matrix} \right]\] that are equal. Since matrices are equal, so their corresponding entries/elements must be equal. So, we will compare both the matrices and we will get, x – y = – 1 and 2x – y = 0. Now using the substitution method, 2x = y, we will solve for x and then for y and then find the value for x + y.
Complete step by step answer:
We are given two matrices \[\left[ \begin{matrix}
x-y & z \\
2x-y & w \\
\end{matrix} \right]\And \left[ \begin{matrix}
-1 & 4 \\
0 & 5 \\
\end{matrix} \right]\] and both the matrices are given as equal and we have to find the value of x + y. We know that two matrices are said to be equal if the corresponding elements of both the matrices are equal.
As we are given that matrix \[\left[ \begin{matrix}
x-y & z \\
2x-y & w \\
\end{matrix} \right]=\left[ \begin{matrix}
-1 & 4 \\
0 & 5 \\
\end{matrix} \right]\] so means that their corresponding entries/elements are the same. Now, we will compare both the matrices to find the required values. We have,
\[\left[ \begin{matrix}
x-y & z \\
2x-y & w \\
\end{matrix} \right]=\left[ \begin{matrix}
-1 & 4 \\
0 & 5 \\
\end{matrix} \right]\]
Comparing both the matrix, we get,
\[x-y=-1.....\left( i \right)\]
\[2x-y=0.....\left( ii \right)\]
\[z=4\]
\[w=5\]
From (ii), we will get,
\[\Rightarrow 2x=y\]
Now, we will use this 2x = y to solve further. Putting y = 2x in (i), we will get,
\[\Rightarrow x-2x=-1\]
\[\Rightarrow -x=-1\]
Cancelling the negative on both the sides, we will get,
\[\Rightarrow x=1\]
Now, as x = 1, putting it in y = 2x, we will get,
\[\Rightarrow y=2\times 1\]
\[\Rightarrow y=2\]
So, as x = 1 and y = 2, we will get,
\[\Rightarrow x+y=1+2=3\]
Note: While solving the matrix, always remember that \[\left| \begin{matrix}
a & b \\
c & d \\
\end{matrix} \right|\] is a sign for the determinant of the matrix while \[\left[ \begin{matrix}
a & b \\
c & d \\
\end{matrix} \right]\] is a symbol. In our question, we are given that the matrices are equal, so we just need to compare the term, and finding the determinant is not required.
x-y & z \\
2x-y & w \\
\end{matrix} \right]\And \left[ \begin{matrix}
-1 & 4 \\
0 & 5 \\
\end{matrix} \right]\] that are equal. Since matrices are equal, so their corresponding entries/elements must be equal. So, we will compare both the matrices and we will get, x – y = – 1 and 2x – y = 0. Now using the substitution method, 2x = y, we will solve for x and then for y and then find the value for x + y.
Complete step by step answer:
We are given two matrices \[\left[ \begin{matrix}
x-y & z \\
2x-y & w \\
\end{matrix} \right]\And \left[ \begin{matrix}
-1 & 4 \\
0 & 5 \\
\end{matrix} \right]\] and both the matrices are given as equal and we have to find the value of x + y. We know that two matrices are said to be equal if the corresponding elements of both the matrices are equal.
As we are given that matrix \[\left[ \begin{matrix}
x-y & z \\
2x-y & w \\
\end{matrix} \right]=\left[ \begin{matrix}
-1 & 4 \\
0 & 5 \\
\end{matrix} \right]\] so means that their corresponding entries/elements are the same. Now, we will compare both the matrices to find the required values. We have,
\[\left[ \begin{matrix}
x-y & z \\
2x-y & w \\
\end{matrix} \right]=\left[ \begin{matrix}
-1 & 4 \\
0 & 5 \\
\end{matrix} \right]\]
Comparing both the matrix, we get,
\[x-y=-1.....\left( i \right)\]
\[2x-y=0.....\left( ii \right)\]
\[z=4\]
\[w=5\]
From (ii), we will get,
\[\Rightarrow 2x=y\]
Now, we will use this 2x = y to solve further. Putting y = 2x in (i), we will get,
\[\Rightarrow x-2x=-1\]
\[\Rightarrow -x=-1\]
Cancelling the negative on both the sides, we will get,
\[\Rightarrow x=1\]
Now, as x = 1, putting it in y = 2x, we will get,
\[\Rightarrow y=2\times 1\]
\[\Rightarrow y=2\]
So, as x = 1 and y = 2, we will get,
\[\Rightarrow x+y=1+2=3\]
Note: While solving the matrix, always remember that \[\left| \begin{matrix}
a & b \\
c & d \\
\end{matrix} \right|\] is a sign for the determinant of the matrix while \[\left[ \begin{matrix}
a & b \\
c & d \\
\end{matrix} \right]\] is a symbol. In our question, we are given that the matrices are equal, so we just need to compare the term, and finding the determinant is not required.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

