 Find the value of the polynomial, $4{{x}^{2}}-5x+3$ when x = 0.(a) 1(b) 2(c) 3(d) 4 Verified
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Hint: To solve this question we first of all should know what is a polynomial, it is an expression of more than 2 algebraic terms of various powers. Here we have to substitute, x = 0 in the given polynomial $4{{x}^{2}}-5x+3$ to get the result.

We are given the polynomial as $4{{x}^{2}}-5x+3$. Here we have ‘x’ is the variable of the given polynomial.
Here we have to find the value of possibility $4{{x}^{2}}-5x+3$ by substituting x = 0 in it.
Then $t=4{{x}^{2}}-5x+3$.
\begin{align} & t=4\times 0-5\times 0+3 \\ & \Rightarrow t=0-0+3 \\ & \Rightarrow t=3 \\ \end{align}
Therefore the value of the polynomial $4{{x}^{2}}-5x+3$ at x = 0 is 3, which is option (c).
Note: If any polynomial has x as denominator of any of terms of it, then x = 0 would give undetermined form and then they are called rational functions. For example if polynomial is of the type $p\left( x \right)=2x+\dfrac{3}{x}+1$, is rational function and not really a polynomial as it has negative powers of x and it can give undetermined form at some values of x.