
Find the value of the given equation \[\sin \left( {\dfrac{\pi }{{12}}} \right)\] using sum and difference identity?
Answer
558.3k+ views
Hint: Sum and difference identity in trigonometry implies the expansion of the given identity with the given sum or difference of the angle, like in algebra we have expansion for the general identity in the same way in trigonometry also we have to follow the rules and solve accordingly.
Formulae Used: \[\sin \left( {a - b} \right) = \sin a\sin b - \cos a\cos b\] , \[\sin \dfrac{\pi }{3} = \dfrac{{\sqrt 3 }}{2},\,\sin \dfrac{\pi }{4} = \cos \dfrac{\pi }{4} = \dfrac{1}{{\sqrt 2 }},\,\cos \dfrac{\pi }{3} = \dfrac{1}{2}\]
Complete step-by-step answer:
For the given trigonometric equation \[\sin \left( {\dfrac{\pi }{{12}}} \right)\]
We can break the given angles as
\[ \Rightarrow \dfrac{\pi }{{12}} = \left( {\dfrac{\pi }{3} - \dfrac{\pi }{4}} \right)\]
To check that above breaking of angle is correct or not we can solve the R.H.S, on solving we get;
\[ \Rightarrow \left( {\dfrac{\pi }{3} - \dfrac{\pi }{4}} \right) = \dfrac{{4\pi - 3\pi }}{{12}} = \dfrac{\pi }{{12}}\left( {L.C.M\,of\,3\,and\,4\,is\,12} \right)\]
Hence our breaking of angle is correct.
Now on further solving and using the trigonometric identity that is:
\[ \Rightarrow \sin \left( {a - b} \right) = \sin a\sin b - \cos a\cos b\]
On comparing our equation with the general equation we get;
\[ \Rightarrow a = \dfrac{\pi }{3},\,b = \dfrac{\pi }{4}\]
Now on solving our equation we get:
\[
\Rightarrow \sin \left( {\dfrac{\pi }{3} - \dfrac{\pi }{4}} \right) = \sin \dfrac{\pi }{3}\sin \dfrac{\pi }{4} - \cos \dfrac{\pi }{3}\cos \dfrac{\pi }{4} \\
= \left( {\dfrac{{\sqrt 3 }}{2} \times \dfrac{1}{{\sqrt 2 }}} \right) - \left( {\dfrac{1}{2} \times \dfrac{1}{{\sqrt 2 }}} \right) \\
= \dfrac{{\sqrt 3 }}{{2\sqrt 2 }} - \dfrac{1}{{2\sqrt 2 }} = \dfrac{{\sqrt 3 - 1}}{{2\sqrt 2 }} \;
\]
This is our required answer.
So, the correct answer is “$\dfrac{{\sqrt 3 - 1}}{{2\sqrt 2 }}$”.
Note: While dealing with bigger angles you should always be aware for the breaking of angles in smaller forms because only smaller angles starting from zero, thirty, forty five, sixty and ninety can be easily remembered and solution can be easily obtained.
Every trigonometric identity has a rule while conversion to its smaller form and you should all convert the angles easily, rules state the plus and minus sign after conversion the angle. While breaking the angle you should know how to break according to our convenience, always try to break in such a way that broken angle value can easily be determined or already known.
Formulae Used: \[\sin \left( {a - b} \right) = \sin a\sin b - \cos a\cos b\] , \[\sin \dfrac{\pi }{3} = \dfrac{{\sqrt 3 }}{2},\,\sin \dfrac{\pi }{4} = \cos \dfrac{\pi }{4} = \dfrac{1}{{\sqrt 2 }},\,\cos \dfrac{\pi }{3} = \dfrac{1}{2}\]
Complete step-by-step answer:
For the given trigonometric equation \[\sin \left( {\dfrac{\pi }{{12}}} \right)\]
We can break the given angles as
\[ \Rightarrow \dfrac{\pi }{{12}} = \left( {\dfrac{\pi }{3} - \dfrac{\pi }{4}} \right)\]
To check that above breaking of angle is correct or not we can solve the R.H.S, on solving we get;
\[ \Rightarrow \left( {\dfrac{\pi }{3} - \dfrac{\pi }{4}} \right) = \dfrac{{4\pi - 3\pi }}{{12}} = \dfrac{\pi }{{12}}\left( {L.C.M\,of\,3\,and\,4\,is\,12} \right)\]
Hence our breaking of angle is correct.
Now on further solving and using the trigonometric identity that is:
\[ \Rightarrow \sin \left( {a - b} \right) = \sin a\sin b - \cos a\cos b\]
On comparing our equation with the general equation we get;
\[ \Rightarrow a = \dfrac{\pi }{3},\,b = \dfrac{\pi }{4}\]
Now on solving our equation we get:
\[
\Rightarrow \sin \left( {\dfrac{\pi }{3} - \dfrac{\pi }{4}} \right) = \sin \dfrac{\pi }{3}\sin \dfrac{\pi }{4} - \cos \dfrac{\pi }{3}\cos \dfrac{\pi }{4} \\
= \left( {\dfrac{{\sqrt 3 }}{2} \times \dfrac{1}{{\sqrt 2 }}} \right) - \left( {\dfrac{1}{2} \times \dfrac{1}{{\sqrt 2 }}} \right) \\
= \dfrac{{\sqrt 3 }}{{2\sqrt 2 }} - \dfrac{1}{{2\sqrt 2 }} = \dfrac{{\sqrt 3 - 1}}{{2\sqrt 2 }} \;
\]
This is our required answer.
So, the correct answer is “$\dfrac{{\sqrt 3 - 1}}{{2\sqrt 2 }}$”.
Note: While dealing with bigger angles you should always be aware for the breaking of angles in smaller forms because only smaller angles starting from zero, thirty, forty five, sixty and ninety can be easily remembered and solution can be easily obtained.
Every trigonometric identity has a rule while conversion to its smaller form and you should all convert the angles easily, rules state the plus and minus sign after conversion the angle. While breaking the angle you should know how to break according to our convenience, always try to break in such a way that broken angle value can easily be determined or already known.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

What is the difference between biodegradable and nonbiodegradable class 11 biology CBSE

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

