Question

How do you find the value of 3 over the square root of 3 ?

Answer 1

Hint: We know that square of square root of x is equal to x. so we can write $\sqrt{x}\times \sqrt{x}$ is equal to x so the value of $\dfrac{x}{\sqrt{x}}$ is equal to $\sqrt{x}$ where x is not equal to 0 . We can use this to find the value of 3 over the square root of 3 or $\dfrac{3}{\sqrt{3}}$ by assuming x equal to 3.

Complete step-by-step solution:
If we convert the statement “find the value of 3 over the square root of 3 “ into equation we get $\dfrac{3}{\sqrt{3}}$
We know that product of $\sqrt{3}$ and $\sqrt{3}$ is equal to 3 , so the value of $\dfrac{3}{\sqrt{3}}$ is equal to $\sqrt{3}$
We can convert $\sqrt{3}$ into decimal up to 2 places which is equal to 1.73 , we can not write the exact value because it is an irrational number. 1.73 is correct value of $\sqrt{3}$ up to 2 decimal places
We can say that the value of $\dfrac{x}{\sqrt{x}}$ is equal to $\sqrt{x}$ where x is not equal to 0.

Note: Always remember $\dfrac{x}{\sqrt{x}}$ is equal to $\sqrt{x}$ where x is not equal to 0 , if x is equal to 0 then denominator will be 0 and The number $\sqrt{x}$ is always irrational if x is not a square number. We can not write an irrational number into fractions or decimal numbers because it is an infinite long non repetitive decimal number.