
Find the super halogen.
A)${F_2}$.
B)$C{l_2}$.
C)$B{r_2}$.
D)${I_2}$.
Answer
525.6k+ views
Hint: We know that Super-halogens have high electronegativity value and they have more structural differences than other halogens. In super-halogen, the halogen atom is surrounded by a metal atom that is present in the core.
Complete step by step answer:Given,
We know that the elements Fluorine, chlorine, bromine, and iodine are belonging to the same group called the halogen family.
As we move down the group the electronegativity value of the elements decreases. The electronegativity values of the halogen family are,
${\text{F - 4}}{\text{.0,Cl - 3}}{\text{.16,Br - 2}}{\text{.96,I - 2}}{\text{.66}}$
Super-halogen is a halogen with high electronegativity and high reactivity.
The electronegativity of fluorine is four which is greatest of all. This means that fluorine is the most chemically active element of all the halogens it combines with every element directly except the oxygen and some of the noble gases. Thus, fluorine is super-halogen.
$\therefore $The option A is correct.
Additional information:
Electronegativity of fluorine:
Electronegativity is the tendency of an element to attract a shared pair of electrons towards itself and as we move down the group electronegativity decreases.
The atomic number of fluorine is ${\text{9}}{\text{.}}$ the electronic configuration of fluorine is ${\text{1}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{p}}^{\text{5}}}{\text{.}}$ Fluorine is the most electronegative because it has five electrons in the valence cell. To get stable electronic configuration fluorine needs only one electron which makes it highly attracted to the electron.
Note:
We have to remember that the noble gas $\left( {{N_g}} \right)$ can form stable mononuclear $\left( {{N_g}{F_7}^ - } \right)$ and dinuclear $\left( {{N_{g2}}{F_{13}}^ - } \right)$ with super-halogen. Super-halogen is also used as an oxidizing agent, biocatalysts, and as building blocks for some industrially important unusual salts.
Complete step by step answer:Given,
We know that the elements Fluorine, chlorine, bromine, and iodine are belonging to the same group called the halogen family.
As we move down the group the electronegativity value of the elements decreases. The electronegativity values of the halogen family are,
${\text{F - 4}}{\text{.0,Cl - 3}}{\text{.16,Br - 2}}{\text{.96,I - 2}}{\text{.66}}$
Super-halogen is a halogen with high electronegativity and high reactivity.
The electronegativity of fluorine is four which is greatest of all. This means that fluorine is the most chemically active element of all the halogens it combines with every element directly except the oxygen and some of the noble gases. Thus, fluorine is super-halogen.
$\therefore $The option A is correct.
Additional information:
Electronegativity of fluorine:
Electronegativity is the tendency of an element to attract a shared pair of electrons towards itself and as we move down the group electronegativity decreases.
The atomic number of fluorine is ${\text{9}}{\text{.}}$ the electronic configuration of fluorine is ${\text{1}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{p}}^{\text{5}}}{\text{.}}$ Fluorine is the most electronegative because it has five electrons in the valence cell. To get stable electronic configuration fluorine needs only one electron which makes it highly attracted to the electron.
Note:
We have to remember that the noble gas $\left( {{N_g}} \right)$ can form stable mononuclear $\left( {{N_g}{F_7}^ - } \right)$ and dinuclear $\left( {{N_{g2}}{F_{13}}^ - } \right)$ with super-halogen. Super-halogen is also used as an oxidizing agent, biocatalysts, and as building blocks for some industrially important unusual salts.
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