
How do you find the square root of 3 to the second power ?
Answer
540.6k+ views
Hint:In order to find the solution of this question , we need to first understand the mathematical terms and should frame to make up the expression . The term ‘ square root ‘ signifies that what should be that number multiplied by itself so that it is the number under the square root symbol called radical . Radical is represented by $\sqrt {} $. For example = 4 , the base part of the value inside the square root such that it contains perfect squares in it that is also by the definition when the number 2 multiplied by itself is equal to the number under the radical or square root symbol.
Formula used:
${(a)^{\dfrac{m}{n}}}$=${({a^m})^{\dfrac{1}{n}}}$
${x^{m + n}} = {x^m} \times {x^n}$
Complete step by step answer:
We are given with the mathematical statements which when framed makes up the expression as -
${\left( {\sqrt 3 } \right)^2}$
First we will try to simplify further by the definition that what should be that number multiplied by itself so that it is the number under the square root symbol . But the value $\sqrt 3 $ cannot be simplified into its factors, So the root we cannot simplify further comes to be surd . Now let’s find the answer by using some formula
\[{({b^m})^n} = {b^{mn}}\]
Also , we know that the square root have the power as $\dfrac{1}{2}$
\[\surd b = {b^{\dfrac{1}{2}}}\]
Some rules of the exponents when applied , we got
$\sqrt 3 = {3^{\dfrac{1}{2}}}$
Let’s consider the formula concerning exponents ${(a)^{\dfrac{m}{n}}}$=${({a^m})^{\dfrac{1}{n}}}$, we get
${\left( {\sqrt 3 } \right)^2}$
Rewriting square root as half power ,
${\left( {{3^{\dfrac{1}{2}}}} \right)^2}$
By applying ,
\[{({b^m})^n} = {b^{mn}}\]
\[\Rightarrow {3^{\dfrac{1}{2} \times 2}}\]
2 gets canceled out and from the above we can say that ${3^1} = 3$.
Therefore, ${\left( {\sqrt 3 } \right)^2}$ in the simplest form $3$.
Note:Do not Forget to cross check the answer.
-The value of root 3 is approximately equal to $1.732$.
-Also root 3 can also be said as a irrational number as it cannot be expressed in the form of a fraction .
-Under the radical symbol $\sqrt {} $ we cannot place a negative number , it should be the positive real number .
-The two halves can't make up the whole one in the same way the two square roots ( having powers as $\dfrac{1}{2}$) can make up the whole one.For example = $\sqrt 3 $multiplied by $\sqrt 3 $gives the number 3 as the base is same so power gets added which makes the power 1 giving us the real positive number 3 .
Formula used:
${(a)^{\dfrac{m}{n}}}$=${({a^m})^{\dfrac{1}{n}}}$
${x^{m + n}} = {x^m} \times {x^n}$
Complete step by step answer:
We are given with the mathematical statements which when framed makes up the expression as -
${\left( {\sqrt 3 } \right)^2}$
First we will try to simplify further by the definition that what should be that number multiplied by itself so that it is the number under the square root symbol . But the value $\sqrt 3 $ cannot be simplified into its factors, So the root we cannot simplify further comes to be surd . Now let’s find the answer by using some formula
\[{({b^m})^n} = {b^{mn}}\]
Also , we know that the square root have the power as $\dfrac{1}{2}$
\[\surd b = {b^{\dfrac{1}{2}}}\]
Some rules of the exponents when applied , we got
$\sqrt 3 = {3^{\dfrac{1}{2}}}$
Let’s consider the formula concerning exponents ${(a)^{\dfrac{m}{n}}}$=${({a^m})^{\dfrac{1}{n}}}$, we get
${\left( {\sqrt 3 } \right)^2}$
Rewriting square root as half power ,
${\left( {{3^{\dfrac{1}{2}}}} \right)^2}$
By applying ,
\[{({b^m})^n} = {b^{mn}}\]
\[\Rightarrow {3^{\dfrac{1}{2} \times 2}}\]
2 gets canceled out and from the above we can say that ${3^1} = 3$.
Therefore, ${\left( {\sqrt 3 } \right)^2}$ in the simplest form $3$.
Note:Do not Forget to cross check the answer.
-The value of root 3 is approximately equal to $1.732$.
-Also root 3 can also be said as a irrational number as it cannot be expressed in the form of a fraction .
-Under the radical symbol $\sqrt {} $ we cannot place a negative number , it should be the positive real number .
-The two halves can't make up the whole one in the same way the two square roots ( having powers as $\dfrac{1}{2}$) can make up the whole one.For example = $\sqrt 3 $multiplied by $\sqrt 3 $gives the number 3 as the base is same so power gets added which makes the power 1 giving us the real positive number 3 .
Recently Updated Pages
Master Class 9 Social Science: Engaging Questions & Answers for Success

Master Class 9 Science: Engaging Questions & Answers for Success

Master Class 9 English: Engaging Questions & Answers for Success

Master Class 9 Maths: Engaging Questions & Answers for Success

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Class 9 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
Which places in India experience sunrise first and class 9 social science CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Write the 6 fundamental rights of India and explain in detail

Difference Between Plant Cell and Animal Cell

What is pollution? How many types of pollution? Define it

What is the Full Form of ISI and RAW


