How do you find the slope and y-intercept of $2x - 5y = - 45$?
Answer
567.6k+ views
Hint: The slope of a line in graph is the change in the value of $y$ with respect to $x$ in the equation, i.e. $m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}$. The y intercept is the point at which the line cuts the y-axis which we can find by putting $x = 0$. Alternatively, we can find the slope of the line and the y-intercept simultaneously by using the slope-intercept formula wherein we write the given equation in the form $y = mx + c$, where $m$ is the slope of the line and $c$ is the y-intercept.
Complete step by step solution:
We have to find the slope and y intercept of the line given by the equation $ - 4x + 2y = - 2$.
We will use the slope-intercept formula to find the slope of the line.
The slope-intercept formula is given by $y = mx + c$.
We can rewrite the given equation in the form,
$
\Rightarrow - 4x + 2y = - 2 \\
\Rightarrow 2y = 4x - 2 \\
\Rightarrow y = \dfrac{4}{2}x - \dfrac{2}{2} \\
\Rightarrow y = 2x - 1 \\
$
On comparing with the standard form of the slope-intercept formula, we see that
$m = 2$ and $c = - 1$
Thus, the slope of the given line is $2$ and the y-intercept is $ - 1$.
Hence, the slope of the line $ - 4x + 2y = - 2$ is $2$ and it cuts the y-axis at the point $(0,{\kern 1pt} {\kern 1pt} {\kern 1pt} - 1)$.
Thus, the slope of the given line is $2$ and the y-intercept is $ - 1$.
Note: For a line making acute angle with the x-axis, the slope is positive as the behavior of $y$ is same as that of $x$, i.e. the value of $y$ increases as the value of $x$ increases and the value of $y$ decreases when the value of $x$ decreases. We can also find the y intercept of the line by putting $x = 0$ in the equation as when the line is cutting the y-axis the value of $x$ is $0$.
Complete step by step solution:
We have to find the slope and y intercept of the line given by the equation $ - 4x + 2y = - 2$.
We will use the slope-intercept formula to find the slope of the line.
The slope-intercept formula is given by $y = mx + c$.
We can rewrite the given equation in the form,
$
\Rightarrow - 4x + 2y = - 2 \\
\Rightarrow 2y = 4x - 2 \\
\Rightarrow y = \dfrac{4}{2}x - \dfrac{2}{2} \\
\Rightarrow y = 2x - 1 \\
$
On comparing with the standard form of the slope-intercept formula, we see that
$m = 2$ and $c = - 1$
Thus, the slope of the given line is $2$ and the y-intercept is $ - 1$.
Hence, the slope of the line $ - 4x + 2y = - 2$ is $2$ and it cuts the y-axis at the point $(0,{\kern 1pt} {\kern 1pt} {\kern 1pt} - 1)$.
Thus, the slope of the given line is $2$ and the y-intercept is $ - 1$.
Note: For a line making acute angle with the x-axis, the slope is positive as the behavior of $y$ is same as that of $x$, i.e. the value of $y$ increases as the value of $x$ increases and the value of $y$ decreases when the value of $x$ decreases. We can also find the y intercept of the line by putting $x = 0$ in the equation as when the line is cutting the y-axis the value of $x$ is $0$.
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