
Find the rationalizing factor of: \[\left( {\sqrt 3 + \sqrt {10} - \sqrt 5 } \right)\]
A. \[\left( {\sqrt 3 + \sqrt {10} + \sqrt 5 } \right)\left( {8 - 2\sqrt {30} } \right)\]
B. \[\left( {\sqrt 3 + \sqrt {10} + \sqrt 5 } \right)\]
C. \[\left( {\sqrt 3 + \sqrt {10} + \sqrt 5 } \right)\left( {8 + 2\sqrt {30} } \right)\]
D. None of the above
Answer
620.1k+ views
Hint: The factor of multiplication by which rationalization is done is called the rationalizing factor. So, rationalize the given expression by using the formula \[\left( {a - b} \right)\left( {a + b} \right) = {a^2} - {b^2}\] twice to obtain the required answer.
Complete step-by-step answer:
Rationalising factor means the term by which we convert irrational numbers to rational numbers.
So, it means we have to choose a term by which we make \[\left( {\sqrt 3 + \sqrt {10} - \sqrt 5 } \right)\] is a rational number.
We know that, \[\left( {a - b} \right)\left( {a + b} \right) = {a^2} - {b^2}\]
Since,
\[
\left( {\sqrt 3 + \sqrt {10} - \sqrt 5 } \right)\left( {\sqrt 3 + \sqrt {10} + \sqrt 5 } \right) = {\left( {\sqrt 3 + \sqrt {10} } \right)^2} - {\left( {\sqrt 5 } \right)^2} \\
\left( {\sqrt 3 + \sqrt {10} - \sqrt 5 } \right)\left( {\sqrt 3 + \sqrt {10} + \sqrt 5 } \right) = 3 + 10 + 2\sqrt 3 \sqrt {10} - 5 \\
\left( {\sqrt 3 + \sqrt {10} - \sqrt 5 } \right)\left( {\sqrt 3 + \sqrt {10} + \sqrt 5 } \right) = 8 + 2\sqrt {30} \\
\]
And
\[
\left( {8 + 2\sqrt {30} } \right)\left( {8 - 2\sqrt {30} } \right) = {8^2} - {\left( {2\sqrt {30} } \right)^2} \\
\left( {8 + 2\sqrt {30} } \right)\left( {8 - 2\sqrt {30} } \right) = 64 - 4 \times 30 \\
\left( {8 + 2\sqrt {30} } \right)\left( {8 - 2\sqrt {30} } \right) = 64 - 120 = - 56 \\
\]
Therefore, \[\left( {\sqrt 3 + \sqrt {10} - \sqrt 5 } \right)\left( {\sqrt 3 + \sqrt {10} + \sqrt 5 } \right)\left( {8 - 2\sqrt {30} } \right) = - 56\] which is a rational number.
Hence, \[\left( {\sqrt 3 + \sqrt {10} + \sqrt 5 } \right)\left( {8 - 2\sqrt {30} } \right)\] is a rational number \[\left( {\sqrt 3 + \sqrt {10} - \sqrt 5 } \right)\].
Thus, the correct option is A. \[\left( {\sqrt 3 + \sqrt {10} + \sqrt 5 } \right)\left( {8 - 2\sqrt {30} } \right)\]
Note: In this question, the given expression \[\left( {\sqrt 3 + \sqrt {10} - \sqrt 5 } \right)\] is a Surd. If the product of two or more surds is a rational number then they are rationalizing factors to each other. Sometimes we divide to get the rationalizing factor.
Complete step-by-step answer:
Rationalising factor means the term by which we convert irrational numbers to rational numbers.
So, it means we have to choose a term by which we make \[\left( {\sqrt 3 + \sqrt {10} - \sqrt 5 } \right)\] is a rational number.
We know that, \[\left( {a - b} \right)\left( {a + b} \right) = {a^2} - {b^2}\]
Since,
\[
\left( {\sqrt 3 + \sqrt {10} - \sqrt 5 } \right)\left( {\sqrt 3 + \sqrt {10} + \sqrt 5 } \right) = {\left( {\sqrt 3 + \sqrt {10} } \right)^2} - {\left( {\sqrt 5 } \right)^2} \\
\left( {\sqrt 3 + \sqrt {10} - \sqrt 5 } \right)\left( {\sqrt 3 + \sqrt {10} + \sqrt 5 } \right) = 3 + 10 + 2\sqrt 3 \sqrt {10} - 5 \\
\left( {\sqrt 3 + \sqrt {10} - \sqrt 5 } \right)\left( {\sqrt 3 + \sqrt {10} + \sqrt 5 } \right) = 8 + 2\sqrt {30} \\
\]
And
\[
\left( {8 + 2\sqrt {30} } \right)\left( {8 - 2\sqrt {30} } \right) = {8^2} - {\left( {2\sqrt {30} } \right)^2} \\
\left( {8 + 2\sqrt {30} } \right)\left( {8 - 2\sqrt {30} } \right) = 64 - 4 \times 30 \\
\left( {8 + 2\sqrt {30} } \right)\left( {8 - 2\sqrt {30} } \right) = 64 - 120 = - 56 \\
\]
Therefore, \[\left( {\sqrt 3 + \sqrt {10} - \sqrt 5 } \right)\left( {\sqrt 3 + \sqrt {10} + \sqrt 5 } \right)\left( {8 - 2\sqrt {30} } \right) = - 56\] which is a rational number.
Hence, \[\left( {\sqrt 3 + \sqrt {10} + \sqrt 5 } \right)\left( {8 - 2\sqrt {30} } \right)\] is a rational number \[\left( {\sqrt 3 + \sqrt {10} - \sqrt 5 } \right)\].
Thus, the correct option is A. \[\left( {\sqrt 3 + \sqrt {10} + \sqrt 5 } \right)\left( {8 - 2\sqrt {30} } \right)\]
Note: In this question, the given expression \[\left( {\sqrt 3 + \sqrt {10} - \sqrt 5 } \right)\] is a Surd. If the product of two or more surds is a rational number then they are rationalizing factors to each other. Sometimes we divide to get the rationalizing factor.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Difference Between Plant Cell and Animal Cell

What is the color of ferrous sulphate crystals? How does this color change after heating? Name the products formed on strongly heating ferrous sulphate crystals. What type of chemical reaction occurs in this type of change.

A narrow strip of water body joining two large water class 9 social science CBSE

What is the Full Form of ICSE / ISC ?

A gulab jamun contains sugar syrup up to about 30 of class 9 maths CBSE

