Question

How do you find the product of $\dfrac{2}{3}$ and $1\dfrac{1}{3}$.

Answer 1

Hint: This problem comes under fraction. Fraction is how many parts of the whole we have. It is represented as \[\dfrac{a}{b}\], where a is a numerator and b is a denominator and a, b are integers b$ \ne $0. Here we have two kinds of fraction proper fraction and mixed fraction. First we need to convert mixed fraction into improper, then we need to find the product of those to fraction. Product is the same as multiplication.

Complete step-by-step solution:
The fractions are $\dfrac{2}{3}$ and $1\dfrac{1}{3}$
Now converting $1\dfrac{1}{3}$ mixed fraction into improper
For that multiply the whole number part to denominator and then add to numeration and we get $\dfrac{4}{3}$
Now the product of $\dfrac{2}{3} \times \dfrac{4}{3}$, we multiply numerator to numerator and denominator to denominator, (If the numbers numerator and denominator are divisible by some common number we can reduce)
Here, the numbers doesn’t have common divisible

Hence the product of $\dfrac{2}{3}$ and $1\dfrac{1}{3}$ is $\dfrac{8}{9}$

Note: The problem related to fraction is likely to have problems on four mathematical operations are addition, subtraction, multiplication and division.
There are three different types of fractions; they are proper, improper and mixed fractions.
If the fraction has a numerator smaller than the denominator then it is a proper fraction.
If the fraction has a numerator greater than the denominator then it is an improper fraction.
From the improper fraction we convert into mixed fraction for that divide the numerator by the denominator.
Write the quotient value as the whole number and remainder as numerator and divisor as denominator.