
Find the multiplicative inverse of the complex number 2-3i.
(a) $2+3i$
(b) $\dfrac{2+3i}{13}$
(c) $-2-3i$
(d) $3i$
Answer
591k+ views
Hint: Think of a complex number which, when multiplied by 2-3i, gives the product 1. Make sure that you convert your answer to suitable form matching with the option. Before moving to the question, let us talk about the multiplicative inverse. The multiplicative inverse of a number is defined as the reciprocal of the number itself. In other words, an expression is said to be the multiplicative inverse of the other if on multiplying, their product is 1.
Complete step-by-step answer:
For example: if $xy=1$ , then, x and y are the multiplicative inverses of each other.
Now, moving to the solution to the question mentioned above.
We are asked to find the multiplicative inverse of 2 – 3i. Let the given complex number be equal to ‘m’.
$\therefore m=2-3i$
Let the multiplicative inverse of m be ‘n.’
Now, according to the definition of the multiplicative inverse:
$mn=1$
$\Rightarrow n=\dfrac{1}{m}$
$\Rightarrow n=\dfrac{1}{2-3i}$
Now, we will multiply and divide the right-hand side of the by (2 + 3i). So, we get:
$n=\dfrac{1}{2-3i}\times \dfrac{2+3i}{2+3i}$
$n=\dfrac{2+3i}{\left( 2+3i \right)\left( 2-3i \right)}$
We know that ${{a}^{2}}-{{b}^{2}}=\left( a+b \right)\left( a-b \right)$ . Using this formula in the denominator of n, we get:
$n=\dfrac{2+3i}{{{2}^{2}}-{{\left( 3i \right)}^{2}}}$
$\Rightarrow n=\dfrac{2+3i}{4-9{{i}^{2}}}$
We know; $i=\sqrt{-1}$
$\therefore {{i}^{2}}=-1$
So, we will substitute $\therefore {{i}^{2}}=-1$ in $n=\dfrac{2+3i}{4-9{{i}^{2}}}$ . So, we get:
$n=\dfrac{2+3i}{4-9(-1)}$
$\Rightarrow n=\dfrac{2+3i}{4+9}$
$\Rightarrow n=\dfrac{2+3i}{13}$
So, the multiplicative inverse of the complex number $2-3i$ is $\dfrac{2+3i}{13}$ .
Therefore, the answer is option (b).
Note: The inverse, in general, refers to multiplicative inverse, but there is a possibility of additive inverse being asked. An expression is said to be the additive inverse of other if both expressions add up, giving 0 as the sum. For example: if $x+y=0$ , then, x and y are the additive inverses of each other. Also, multiplicative inverse and reciprocal are the same in case of numbers. Generally, students make a mistake in the expression of ${{2}^{2}}-{{\left( 3i \right)}^{2}}$ . They calculate the value as $4-9=-5$ , which is wrong.
Complete step-by-step answer:
For example: if $xy=1$ , then, x and y are the multiplicative inverses of each other.
Now, moving to the solution to the question mentioned above.
We are asked to find the multiplicative inverse of 2 – 3i. Let the given complex number be equal to ‘m’.
$\therefore m=2-3i$
Let the multiplicative inverse of m be ‘n.’
Now, according to the definition of the multiplicative inverse:
$mn=1$
$\Rightarrow n=\dfrac{1}{m}$
$\Rightarrow n=\dfrac{1}{2-3i}$
Now, we will multiply and divide the right-hand side of the by (2 + 3i). So, we get:
$n=\dfrac{1}{2-3i}\times \dfrac{2+3i}{2+3i}$
$n=\dfrac{2+3i}{\left( 2+3i \right)\left( 2-3i \right)}$
We know that ${{a}^{2}}-{{b}^{2}}=\left( a+b \right)\left( a-b \right)$ . Using this formula in the denominator of n, we get:
$n=\dfrac{2+3i}{{{2}^{2}}-{{\left( 3i \right)}^{2}}}$
$\Rightarrow n=\dfrac{2+3i}{4-9{{i}^{2}}}$
We know; $i=\sqrt{-1}$
$\therefore {{i}^{2}}=-1$
So, we will substitute $\therefore {{i}^{2}}=-1$ in $n=\dfrac{2+3i}{4-9{{i}^{2}}}$ . So, we get:
$n=\dfrac{2+3i}{4-9(-1)}$
$\Rightarrow n=\dfrac{2+3i}{4+9}$
$\Rightarrow n=\dfrac{2+3i}{13}$
So, the multiplicative inverse of the complex number $2-3i$ is $\dfrac{2+3i}{13}$ .
Therefore, the answer is option (b).
Note: The inverse, in general, refers to multiplicative inverse, but there is a possibility of additive inverse being asked. An expression is said to be the additive inverse of other if both expressions add up, giving 0 as the sum. For example: if $x+y=0$ , then, x and y are the additive inverses of each other. Also, multiplicative inverse and reciprocal are the same in case of numbers. Generally, students make a mistake in the expression of ${{2}^{2}}-{{\left( 3i \right)}^{2}}$ . They calculate the value as $4-9=-5$ , which is wrong.
Recently Updated Pages
Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

If overrightarrow a overrightarrow b overrightarrow class 12 maths CBSE

If a b and c are unit coplanar vectors then left 2a class 12 maths CBSE

Master Class 12 Economics: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

How much time does it take to bleed after eating p class 12 biology CBSE

Draw ray diagrams each showing i myopic eye and ii class 12 physics CBSE

Give 10 examples of unisexual and bisexual flowers

